search for: lcog1

Hello all, Frustrated and i know you can help I need to drop the last numeral of each of my values in my data set. So for the following i have tried the ?substring but since i have to specify the length, but because my data are of varying lengths it doenst work so well Data<-c("1131", "1132", "1731" ,"1732" ,"1821" ,"1822",

Hi all For the data below, I would like to return a logical value indicating differences in the data. #Create data Data..<-data.frame(a=rep(1,10),b=c(rep(1,9),2),c=c(rep(1,8),2,2)) a b c 1 1 1 1 2 1 1 1 3 1 1 1 4 1 1 1 5 1 1 1 6 1 1 1 7 1 1 1 8 1 1 1 9 1 1 2 10 1 2 2 So what I want is to return logical value telling me if all the values are the same. So the result would be a b

Hi everyone, I am posting this because i know its easy and i cant for the life of me figure out how to do it though i have tried and through a ridiculously complex loop made it happen. I need to convert some list elements of NULL value to 0s so they mesh with my data frame properly. So for A<-list(1,NULL) returns [[1]] [1] 1 [[2]] NULL Would instead return [[1]] [1] 1 [[2]] [1] 0

Hi , SO i have been on a role of asking simple questions lately. So much for feeling like im getting this R business. I wrote a script 2 weeks ago that utilized "proportion" to turn values in a table (from "table") into proportions to then graph. I now get an error that proportion is not a function so im confused. I ran the script a few times and im thinking maybe i had

Hey R'rs, So im sick of dealing with ESRI products and am looking to stream line a process i now use GIS to do using R. I have made a lot of maps using R but have not yet seen a map that puts pie charts within the map to help represent data like the attachment. http://r.789695.n4.nabble.com/file/n2318816/template1.bmp I found Tanimura et al. work "Proportional Symbol Mapping in

Okay everyone heres a likely softball for someone. Consider the following data frame: #Create data x<-rep(c(1,15),10) y<-rnorm(20) z<-c(rep("auto",10),rep("bus",10)) a<-rep(c(1,1,2,2,3,3,4,4,5,5),2) #Create Data frame Df<-data.frame(Source=x,Rate=y,Bin=a,Type=z) I want to create a new column the equals the sum of the Rates for each type (1,15) by Bin. A

Hello all, I cannot seem to figure out this seemingly simple procedure. I want to sort a data frame by a specified character vector. So for : df.. <- data.frame(Season=rep(c("Summer","Fall","Winter","Spring"),4),Obs= runif(length(rep(c("Summer","Fall","Winter","Spring"),4)))) I want to sort the data frame

Hi everyone, I looked around the list for a while but couldn't find a solution to my problem. I am storing some results to a simulation in a list and for each element i have two separate vectors(is that what they are called, correct my vocab if necessary). See below Version1_<-list() for(i in 1:5){ Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1)) } What I want is to put all

Hi all, I have toyed with this for too long today and in the past i used multiple lines of code to get at what i want. Consider the following: All i need to do is subset Pc to the values that do not equal Pc.X. The first attempt doesnt work because i have unequal lengths. The second attempt doesnt give me an the right answer.

Basic question, looked through the forum and documentation but didnt see a solution. So consider O<-c(1:20) D<-c("1:","2:","3:","4:","5:","6:","7:","8:","9:","10:","11:","12:","13:","14:","15:","16:",

Hey everyone, Im getting better at plotting my data but cant for the life of me figure out how to show a line graph with missing data that doesnt continue the line down to zero then back up to the remaining values. Consider the following x<-c(1:5,0,0,8:10) y<-1:10 plot(0,0,xlim=c(0,10), ylim=c(0,10),type="n",main="Dont show the bloody 0 values!!") lines(x~y,

Hi everyone I have some records that include a date attribute for the date and time but i need to separate the data and analyze it separately in GIS by Month and Year, so i need to pull these attributes out and create their own attribute field. So the input: RawData2.. returns ID period_end_date 1 22 9/10/2007 0:00:00 2 44 2/2/2006 0:00:00 and i need to get ID period_end_date

So after about 4 hours struggling with Try and TryCatch I am throwing in the towel. I have a more complicated function that used logspline through iterative distributions and at some point the logspline doesnt function correctly for some subsets but is fine with others so I need to be able to identify when the error occurs and stop curtailing the distribution and I think this Try or TryCatch

Hello all , This is a pretty simple question I think but cannot find an answer on the list or in my brain. I would like to iterate through a loop and use a vector of strings to name a number of list elements. For instance #Create vector of strings Et<- c("ACC","RTL","WHL") MeanValues_ <- list("ACC" = 1000, "RTL" = 2000,

Hi guys, I have a crap load of data to parse and have enjoyed creating a script that takes this data and creates a number of useful graphics for our area. I am unable to figure out one summary though and its all cause I dont fully understand the apply family of functions. Consider the following: #Create data

Well im thoroughly frustrated after 25 minutes of checking and rechecking my path. What do i not know about loading a mdb that is keeping me from loading my data. i have loaded the Hmisc library and pointed it too my data using mdb.get and continue to get the following error. Error in system(paste("mdb-tables -1", file), intern = TRUE) : 'mdb-tables' not found Which i

Hello all, I am trying to use the tapply function to sum some values and change the column names of the resulting vector. I input Emp Et 1 10565 ACC 2 7515 ADM 3 625 AGF 4 6243 CNS 5 12721 EDU 6 3924 FIN 7 18140 HLH 8 3686 INF 9 15841 MFG 10 243 MIN 11 1864 MNG 12 4664 OSV 13 5496 PRF 14 4988 PUB 15 2166 REC 16 2153 REL 17 16082 RTL 18 3582 TRN 19 757 UTL 20

Hi guys, Cant seem to find a solution for this. I am looking for a substitute for cut that can transform character vectors. So as cut would be used below to transform YearCat-> YearCat2 base on Year and vector Ag<-c("00-'70","'71-'75","'76-'85","'86-'09") using 'cut '

Greetings all, please consider the following data: #Build Data frame Slope<-c(1.291370, 12.208500, 2.110930, 0.578990, 5.019520, 0.807444, 0.554079 , 1.257080, 0.241504 , 0.184337 , 0.383044 , 0.342021) Exposure<-c(790.54, 1167.79 , 845.58 , 1082.47 , 1189.61 , 677.17 , 2058.56 , 469.09 , 112.02 , 803.31 , 254.14 ,1336.16) FwyDist<-c(11809.4222 ,10623.0458, 12279.6271,

Hi everyone, I have been using R too long to have to ask this but here i am. How do i create a separate bin for the 0 value? So for: #Create data frame DF<-data.frame(A=0:20) #Create label vector labs<-1:6 #Create buckets and label DF$Cut<-cut(DF$A,c(0,4,8,12,14,16,20),labels=labs,include.lowest=TRUE) I want the 0(zero) value to be in a separate bin. Sorry for the lame post...