search for: lats

Hi R users, Wonder if somebody could give me help on how to reshape this type of data: ----------------------------------------------------------------------------------------------------------------------- Date:10.09.19 Time:21:39:05 Lat:N62.37.18 Long:E018.07.32 0000-0010 | 28| 28 0010-0020| 302| 302 0020-0030| 42| 42 0030-0040| 2| 2 0040-0050| 1| 1 0060-0070| 1| 1

Hi All, I have a netcdf gridded file with LCC projection. I can easily use image.plot to visualize it. However, as the axises are in X,Y, not Lat and Lon, I could not add state or country maps onto it (or lat lon information). I do have a grid2d file that describes the lat and lon for each (X,Y) grid, but the lat and lon are not regularly spaced, so I could not use image.plot. Does anyone know

Hi folks, The following are initial virtio-scsi + target vhost benchmark results using multiple target LUNs per vhost and multiple virtio PCI adapters to scale the total number of virtio-scsi LUNs into a single KVM guest. The test setup is currently using 4x SCSI LUNs per vhost WWPN, with 8x virtio PCI adapters for a total of 32x 500MB ramdisk LUNs into a single guest, along with each backend

Hi folks, The following are initial virtio-scsi + target vhost benchmark results using multiple target LUNs per vhost and multiple virtio PCI adapters to scale the total number of virtio-scsi LUNs into a single KVM guest. The test setup is currently using 4x SCSI LUNs per vhost WWPN, with 8x virtio PCI adapters for a total of 32x 500MB ramdisk LUNs into a single guest, along with each backend

...alysis, and the first step is to calculate the geographic distance between my study sites. I am hoping to use earth.dist because it allows for multiple pairwise distances to be calculated at one time. I have done a sample calculation, and I seem to have a problem between the steps of using create.lats and earth.dist. I've copied the steps I've taken in R since I am NOT computer literate and have a real problem debugging computer programming. Hopefully someone can help. > create.lats(weatherstations,loc="locality",long="longitude",lat="latitude")...

Hi, I'm trying to read a subset of a netcdf file into R, but although I'm relatively experienced using R, I'm still new to netCDF files, so this may be a very simple/stupid question! I've included an example of the type of file I'm looking at here. www.met.reading.ac.uk/~swp06hg/ccd1983_01-dk1_20.nc (~7Mb) It's a 2D array of the variable CCD along with its lat and

Hi, I'm having trouble with the "which" or the "seq" function, I'm not sure. Here's an example : > lat=seq(1,2,by=0.1) > lat [1] 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 > which(lat==1) [1] 1 > which(lat==1.1) [1] 2 > which(lat==1.2) [1] 3 > which(lat==1.3) [1] 4 > which(lat==1.4) [1] 5 > which(lat==1.5) [1] 6 >

...but the passed data array has 37440 entries!" [[1]] [1] 6 Warning message: In 1:nt : numerical expression has 26 elements: only the first used ################# function for writing out the netcdf file ############# write.netcdf.time <- function(filename='outputfile.nc',data,lons,lats,nt){ lon <- dim.def.ncdf('lon','degrees_east',lons) lat <- dim.def.ncdf('lat','degrees_north',lats) times <- 1:nt tdim <- dim.def.ncdf('time','days since 1980-01-01', times, unlim=TRUE) # levs <- dim.def.ncdf('lev','pressure...

...but the passed data array has 37440 entries!" [[1]] [1] 6 Warning message: In 1:nt : numerical expression has 26 elements: only the first used ################# function for writing out the netcdf file ############# write.netcdf.time <- function(filename='outputfile.nc',data,lons,lats,nt){ lon <- dim.def.ncdf('lon','degrees_east',lons) lat <- dim.def.ncdf('lat','degrees_north',lats) times <- 1:nt tdim <- dim.def.ncdf('time','days since 1980-01-01', times, unlim=TRUE) # levs <- dim.def.ncdf('lev','pressure...

Hello, I am trying to match lat/lon from one dataset with the lat/lon from a second dataset and use that rows data for calculations. I am using match, but this is finding the first match and not comparing the pair, how can I determine if the lat/lon are the same? See example below. Is there a better way to determine to a matching pair of lat/lon values? Example Datasets: > data2

Hi, I try to use a substitute function to generalise a equation. I have this: expression(1+2*pred+3*lat) I need to define the equation in function of x1 and x2 variables. Also I try to define who is x1 and x2. I try this: X1 <- "pred" X2 <- "lat" Now I need substitute pred and lat in equation by x1 and x2 defined on X1 and X2 above, I try this way: >

Hi lily, It's not too hard to do it using dataframes. Getting the indexing right is usually that hardest part: # these values are the centers of the black cells lat<-rep(28:38,11) lon<-rep(98:108,each=11) pop<-sample(80:200,121) # just use the data.frame function blackcells<-data.frame(lat=lat,lon=lon,pop=pop) plot(0,type="n",xlim=c(97.5,108.5),ylim=c(27.5,38.5),

Thank you for your help in advance. I am trying to pull some data back from a web service library(httr) sample2 <- GET("https://elevation.mapzen.com/height?json={\"range\":false,\"shape\":[{\"lat\":40.7,\"lon\":-76.5}]}&api_key=mycode") result2 <- content(sample2) height <- result2$height[[1]] I would like to put by own latitude

...every ordered pair in D2 to the current ordered pair [i] of D1, assign a value for D1$neighbor.id[i] based on D2$point.id[(which.min(dist.geo)], and move on to the next ordered pair of D1 to create another dist.geo, assign another neighbor.id, etc. There are no missings/NAs in any of the longs, lats or point.ids, although advice on generalizing this to deal with them would be appreciated. What I've been trying: neighbor.id <- vector(length=length(D1$lat)) dist.geo <- vector(length=length(D2$lat)) for(i in 1:length(neighbor.id)){ for(j in 1:length(dist.geo)){ dist.geo[j] <-...

Dear all, I have a dataframe of 3 columns, consisting of 'longitude', 'latitude' and a corresponding 'value'. Where identical 'longitude' and 'latitude' pairs occur more than once, I want their corresponding 'value' to be summed and the 'pair' to only appear once. For example: long lat value 10 20 5 6 2 3

a) you need to read the help pages on the paste function... more likely you are looking for the paste0 function because extra spaces will most likely break the GET request format. b) quotes do not become "stuck" as \" ... that is a visual representation intended to clarify that that quote is not terminating the string but is actually part of it. If you want to see the contents

Dear all, maybe somebody can provide some help for this problem: Example: I've got the following dataframe "data": grid.id<-c(1:4) lat<-c(10,12,13,15) species1<-c(0,0,0,1) species2<-c(1,1,0,0) species3<-c(1,1,1,1) data<-data.frame(cbind(grid.id,lat,species1,species2,species3)) How can I, out of "data" make a new dataframe, where the cells of value

Has anyone coded (in R) a spatial voter model with mutation (e.g., Kimura and Weiss 1964, Holley and Liggett 1975, Durrett and Levin 1996)? In principle, it is quite straightforward, but useful simulations require many many iterations, making my "straightforward" version too time intensive. I am happy to share my version (without mutation, below), for what it is worth. Thank you in

r-help lattice adepts: I have a question which is somewhat geospatial, so I posted to r-sig-geo rather than here: https://stat.ethz.ch/pipermail/r-sig-geo/2012-November/016757.html > summary: How to overlay a geographical map on each panel in a lattice > (or Trellis), e.g., of levelplot's? Note I am not inquiring about > creating choropleth maps[,] which Sarkar 2008 covers quite

Dear all, I have a big file containing latitude points(-10 to 80) and corresponding values. Example data Lat=c(69.48134, 69.49439, 69.50736, 69.52026, 69.52438, 69.53308, 69.53746, 69.54365, 69.54582, 69.6884, 69.69272, 69.998, 70.00055, 70.00106, 70.00295, 70.00308, 70.00363, 70.00427, 70.00665, 70.00906, 70.01049, 70.01053, 70.01075, 70.01208, 70.01236, 70.01418, 70.01452, 70.01646,