search for: lati

Hi, I'm trying to use transform my mercator locations into utm but I'm doing something wrong because only x is transformed ... see > xy.sp SpatialPoints: loni lati [1,] -8.85 38.16 [2,] -9.19 37.99 [3,] -9.11 37.97 [4,] -9.06 38.15 [5,] -9.03 37.87 [6,] -9.14 37.81 [7,] -9.09 37.70 [8,] -8.95 37.45 [9,] -9.17 37.37 [10,] -9.00 37.34 Coordinate Reference System (CRS) arguments: +proj=merc +datum=WGS84 > transform(xy.sp, CRS("+proj=ut...

...42.35, 42.62, 42.83, 44.62, 43.62), longF = c(82.25, 81.77, 81.37, 79.92, 85.5, 85.25), latG = c(42.05, 42.23, 42.37, 42.37, 44.75, 44.03), longG = c(82.88, 82.35, 81.3, 80.03, 83.57, 83.47), latH = c(42.15, 42.38, 42.53, 42.87, 44.47, 44.03), longH = c(81.63, 80.78, 80.35, 78.73, 81.75, 81.72), latI = c(42.03, 42.25, 42.33, 42.33, 44.75, 44.03), longI = c(83.53, 82.45, 81.98, 80.65, 84.33, 84.22), latJ = c(42.02, 42.12, 42.5, 42.68, 44.35, 44.07), longJ = c(82.9, 82.42, 81.87, 80.15, 82.9, 83.6), latK = c(42, 42.08, 42.48, 42.67, 44.32, 44.03), longK = c(82.9, 82.37, 81.87, 80.18, 82.9, 83.57)...

...the 6th column (which contains labels: character string, 2 missing values) and the 93th row. The particular values in this record do not seem to matter: they are not the same in the Access table and in the FoxPro table (tables are the same but order is different). > vill[50:54, ] codelieu lati hemi longi meri nom 50 SNKOLDJI 12.8436 N 15.0192 O Djida Marietou 51 SNKOLHAM 12.9519 N 14.8467 O SARE HAMIDOU 52 SNKOLKIS 12.9767 N 14.8714 O MARAKISSA 53 SNKOLLAM 12.8594 N 15.0219 O SARE LAMINE...

...first 72*36 matrix. This is how I did: > two=data1[,1:36] Error in data1[, 1:36] : incorrect number of dimensions Do you have any idea how I should fix this? *2) *I thought about another way to deal with this problem. Firstly, I name the each column variable: >colnames(data1)=paste('lati',1:36) and then select: >one=subset(data1,subset=TRUE, select = lati1:lati36) but the problem is that, although I tried to select only 36 columns, above command selects the all columns. (36*1916 =68976) I think if I can name all the variables at one time, say , colnames(data1)=paste('...

Hola a todos. Soy nuevo en R, estoy aprendiendo con tutoriales y lo hago sin un fin comercial y/o laboral. Necesito ayuda para mostrar un mapa y sobre ese mapa poner un punto dado por una coordenada. con esto consigo mostrar el mapa. library(raster) arg<-getData('GADM', country='ARG', level=0) plot(arg) En ese mapa quiero mostrar un punto que está en el sistema de

Hi, I'm running some databases's software on a CentOS 4.5 server and I'd like to know if there are any audit software in CentOS4.5 CDs packages?.....I need some software to audit all the files on the server, I mean, if some one delete a file, or change some permissions on any filesystems, if someone copy files to my server and some of this stuff... take in mind I'm not lookign for

...="20" type="text" onkeyup="new Ajax.Autocompleter(''autocomplete'', ''autocomplete_choices'', ''list.php'', {minChars: 2,afterUpdateElement: auto_complete_on_select} );"/> <br/> lati: <input id="inputlat" type="text" value="-" /> <br/> long: <input id="inputlong" type="text" value="-" /> Thanks in advance max -- Posted via http://www.ruby-forum.com/.

...low. Why do you use > abs(blackcells[[i]]$lat - redcell$lat) <1 rather than a different number > than 1? Second, why to construct blackcells as a list, rather than a > dataframe. Because in a dataframe, each row can represent one grid cell, > while the three columns can represent the lati, lon, and pop. Thanks again > for your help. > > for(i in 1:121) { > if(abs(blackcells[[i]]$lat-redcell$lat) < 1 && > abs(blackcells[[i]]$lon-redcell$lon) < 1) { > close4[closen]<-i > closen<-closen+1 > } > } > > On Wed, May 16, 2018 at 2:45 AM,...

Hi lily, There are one or two assumptions to be made here. First is that the latitude and longitude values of the "black" cells are equally spaced as in your illustration. Second, that all latitude and longitude values for the "red" cells fall at the corners of four "black" cells. You can get the four "black" cells by finding the lat/lon...

Hi R users, I have a question about data processing. I have such a dataset, while each black grid cell has a few attributes and the corresponding attribute values. The latitude and longitude of the center of each grid cell are given also. Then I want to average the attribute values from four adjacent grid cells to get the average value for the center of each red grid cell. Thus, there are the same number of attributes, but different values. The red grid cells do not...