search for: lat2

...,pop=pop) plot(0,type="n",xlim=c(97.5,108.5),ylim=c(27.5,38.5), xlab="Longitude",ylab="Latitude") abline(h=27.5) abline(h=lat+0.5) abline(v=97.5) abline(v=lon+0.5) text(blackcells$lon,blackcells$lat,pop) # the red cells will be centered on the corners of 4 black cells lat2<-rep(seq(28.5,34.5,by=2),4) lon2<-rep(seq(99.5,105.5,by=2),each=4) redcells<-data.frame(lat=lat2,lon=lon2,value=NA) display the red cells rect(lon2-1,lat2-1,lon2+1,lat2+1,border="red",lwd=2) nblackcells<-dim(blackcells)[1] nredcells<-dim(redcells)[1] for(redcell in 1:nredce...

...n (degree) { radian = degree * (pi/180.0) return(radian) } #radians to degrees Degrees <- function (radian) { degree = radian * (180.0/pi) return(degree) } # Calculates the distance between two points using the # Spherical Law of Cosines gcd.slc <- function(lon1, lat1, lon2, lat2) { R = 6371.0 # Earth mean radius [km] lon1 = Radians(lon1) lat1 = Radians(lat1) lon2 = Radians(lon2) lat2 = Radians(lat2) d = acos(sin(lat1)*sin(lat2) + cos(lat1)*cos(lat2) * cos(lon2-lon1)) * R return(d) # Distance in km } ##############...

...release: R 2.0.0 editor: GNU Emacs 21.3.2 front-end: ESS 5.2.3 --------------------------------- Colleagues Is there a function to calculate distances between adjacent latitude/ longitude pairs in a matrix? It is basically a spatial diff() function that I have in mind. Data: long1, lat1 long2, lat2 long3, lat3 looking for: diff(data$long, data$lat) function Result long1, lat1 long2, lat2, distance = long/lat2 - long/lat1 long3, lat3, distance = long/lat3 - long/lat2 I've probably missed it but a search of the maillist archives and quick scan of the packages (map*) did not solve my que...

...> data2 V1 V2 V3 1 -123.76 47.82 8 2 -123.75 47.82 11 > data[1:2] V1 V2 1 47.82 -123.76 2 47.82 -123.75 3 47.82 -123.74 4 47.82 -123.73 #Subset of current R code : lat <- data$V1 lon <- data$V2 yrs <- c(1,2,5,10,25,50,100,200,500,1000) lon2 <- data2$V1 lat2 <- data2$V2 ppt2 <- data2$V3 for(i in 1:length(lat2)) { loc <- match(lat2[i],lat) loc2 <- match(lon2[i], lon) print(loc); print(loc2) #Need to test to make sure loc equals loc2 freq_ppt <- c(data[i,4],data[i,6],data[i,8],data[i,10],data[i,12...

...=c(97.5,108.5),ylim=c(27.5,38.5), > xlab="Longitude",ylab="Latitude") > abline(h=27.5) > abline(h=lat+0.5) > abline(v=97.5) > abline(v=lon+0.5) > text(blackcells$lon,blackcells$lat,pop) > # the red cells will be centered on the corners of 4 black cells > lat2<-rep(seq(28.5,34.5,by=2),4) > lon2<-rep(seq(99.5,105.5,by=2),each=4) > redcells<-data.frame(lat=lat2,lon=lon2,value=NA) > display the red cells > rect(lon2-1,lat2-1,lon2+1,lat2+1,border="red",lwd=2) > nblackcells<-dim(blackcells)[1] > nredcells<-dim(redcel...

I am wondering if there is a function which will do a join between 2 data.frames by minimum distance, as it is done in ArcGIS for example. For people who are not familiar with ArcGIS here it is an explanation: Suppose you have a data.frame with x, y, coordinates called track, and a second data frame with different x, y coordinates and some other attributes called classif. The track data.frame has

Dear R users, I need to find the coordinates for the point (midpoint) located half way between two pairs of coordinates (lon1,lat1 and lon2,lat2) assuming a straight line between them. What would be the best way? I tried to find an answer in the help archives but without success. I would greatly appreciate any help. df<- data.frame(lon1=c(-4.568,-4.3980), lat1=c(59.235,56.369), lon2=c(-5.123,-4.698), lat2=c(60.258,59.197) ) Thanking in...

...pvalxx <- which(kc$predict < 0) kc$predict[pvalxx] <- 0 pptpred <- kc$predict }else{ pptpred <- 0*(1:pdim[1]) }} newpptpred <- matrix(pptpred, nrow=62, ncol=165) # need to fit the lat/lon frame plat <- seq(37.5,42,by=0.07273)plon <- seq(-105.5,-93.5,by=0.07273) lat2 <- which((plat> 37)&(plat< 42))lon2 <- which((plon> -106)&(plon< -93)) newpptpred <- tpptpred[lat2,pon2] nLevel <- 60 quartz()filled.contour(plon,plat,t(newpredppt),col=rainbow(nLevel),plot.axes={axis(1);axis(2)}) -------------- next part -------------...

Hi, I have a set of locations defined by longitude and latitude (in degrees), and want to calculate the spatial (or geographic) distance among all locations. I did not find such a function in the spatial-related packages. (I *cannot* use 'dist', as I have geographic, not cartesian coordinates). thanks! Robert Robert Ptacnik Norwegian Institute for Water Research (NIVA) Gaustadall?en 21

All - I have a large data frame that looks like ID p1 p2 p3...p20 Lat1 Lat2 Lat3...Lat20 Long1 Long2 Long3...Long20 1 0 0 1 0 NA NA 29.xx NA NA NA -89.xx NA 2 1 0 0 1 27.xx NA NA 29.00 -88.00 NA NA -89.xx 3 0 0 0 0...

Do you have a preferred programming pattern for adding functionality to an ActiveRecord? As an example, say I have some gnarly trig functions for distance and bearing between pairs of latitude and longitude: === file: latlng.rb module LatLng def haversine_distance(lat1, lng1, lat2, lng2) ... end def bearing(lat1, lng1, lat2, lng2) ... end === EOF ... and I want to mix in haversine_distance(other_ar) and bearing(other_ar) methods into an ActiveRecord. The shim functions would look like this: === def haversine_distance(other_ar) haversine_distance(self.lat, self.lng...

.../samba-tool domain classicupgrade, I will see error: "Conversion error: Incomplete multibyte sequence" I had in my old smb.conf: display charset = iso8859-2 dos charset = cp852 unix charset = iso8859-2 In i18n: LANG="cs_CZ" SUPPORTED="cs_CZ:cs:en_US:en" SYSFONT="lat2-sun16" SYSFONTACM="iso02" I am thinking probable cause is encode file passdb.tdb Could you please solution to this? Thank you, Honza

Deemed colleagues I would appreciate your help with a sentence to calculate the linear distance between 2 geographical points (coordinates in UTM). In advance thnks for your attention, -- Ricardo Bandin Llanos rbandin@udec.cl Estudiante - Magíster Cs. m. Pesquerías Universidad de Concepción, Región del Bio-Bio, Chile Celular: (0056-41) 97949957 [[alternative HTML version deleted]]

...nts. And there are very few of them: file * | grep -v "Linux/i386 PC Screen Font v1" eurlatgr.psfu: Linux/i386 PC Screen Font v1 data, 512 characters, Unicode directory, 8x16 lat0-sun16.psfu: Linux/i386 PC Screen Font v1 data, 256 characters, Unicode directory, 8x16 lat2-sun16.psfu: Linux/i386 PC Screen Font v1 data, 256 characters, Unicode directory, 8x16 latarcyrheb-sun16.psfu: Linux/i386 PC Screen Font v1 data, 512 characters, Unicode directory, 8x16 LatGrkCyr-8x16.psfu: Linux/i386 PC Screen Font v1 data, 512 characters, Unicode directory, 8x1...

Hello, This is what I am trying to do: I wrote a little function that takes addresses (coordinates) as input, and returns the road distance between every two points using Google Maps. Catch is, there are 2000 addresses, so I have to get around 2x10^6 addresses. On my first go, this is what I did: ######################################### getRoadDist = function(X,complete=F){ # X must be a

Hi, On 26/10/2019 11:53, Ady Ady via Syslinux wrote: > >> Hi. >> I was trying to make syslinux to display russian letters. >> >> This page >> https://wiki.syslinux.org/wiki/index.php?title=Directives/font says >> that for Cyrillic you need a CP855. Is that correct? All other >> guides in internet say that you need CP866. > > > The