search for: lapplybi

Dear Ruser's I want to substitute each "NA" by the group mean of which the "NA" is belonging to. For example, substitute the first record of traits "NA" by the mean of "BSPy01-10" in the dummy dataframe. I have ever tried to solve this problem by using doBy package. But, I failed. I ask for the advice on how to use "lapplyBy" function of

Hello all R users, I have a problems transforming (or maybe better regrouping) a data.frame. I have a big data.frame, which I would like to sum up according to a specific column. This is an example of my matrix: ID gen 0042787 gen2 0016070 gen2 0016070 gen3 0007409 Gen1 0007409 gen3 0006511 gen2 0006417 gen3 0016070 gen4 0006511 gen4 I want to rearrange the matrix

Dear Ruser's I ask for helps on how to substitute missing values (NAs) by mean of the group it is belonging to. my dummy dataframe is: > df group traits 1 BSPy01-10 NA 2 BSPy01-10 7.3 3 BSPy01-10 7.3 4 BSPy01-11 5.3 5 BSPy01-11 5.4 6 BSPy01-11 5.6 7 BSPy01-11 NA 8 BSPy01-11 NA 9 BSPy01-11 4.8 10 BSPy01-12 8.1 11 BSPy01-12 6.0 12

All - I have data that looks like psd Species Lake Length Weight St.weight Wr Wr.1 vol 432 substock SMB Clear 150 41.00 0.01 95.12438 95.10118 0.0105 433 substock SMB Clear 152 39.00 0.01 86.72916 86.70692 0.0105 434 substock SMB Clear 152 40.00 3.11 88.95298 82.03689 3.2655 435 substock SMB Clear

Hello, Are there any R functions available for performing a serial correlation test for short time series (e.g, series having between 10-14 observations)? Many thanks! Isabella R. Ghement, Ph.D. Ghement Statistical Consulting Company 301-7031 Blundell Road, Richmond, B.C., Canada, V6Y 1J5 Tel: 604-767-1250 Fax: 604-270-3922 E-mail: isabella at ghement.ca Web: www.ghement.ca -----Original