search for: lannajin

Hi Everyone, Does anyone know of any projects for running an interactive R session within a web browser? I'm looking for something similar to the one on the Ruby website (http://tryruby.org), except for R. Thanks for your responses in advance! Lanna ----- Lanna Jin lannajin at gmail.com 510-898-8525 -- View this message in context: http://r.789695.n4.nabble.com/R-for-web-browser-tp2125571p2125571.html Sent from the R help mailing list archive at Nabble.com.

...encountering issues individually indexing the tables and converting them into matrices in one fell swoop. r1997<-as.matrix(tableT[,,"1997"]) #How I would do it individually; but I can I make matrices for each year as a function? Thanks in advance for your suggestions! -- Lanna Jin lannajin@gmail.com 510-898-8525 [[alternative HTML version deleted]]

...frame$Year) the plot is wrong, probably because the dataframe has unnecessary repeats of values. I also tried converting all2 into a ftable (also tried a matrix) and naming the columns and rows and evoking them in the xyplot. But this has also turned disasterous. Thanks in advance! -- Lanna Jin lannajin@gmail.com 510-898-8525 [[alternative HTML version deleted]]

I need to replace <NA> occurrences in multiple columns in a data.frame with "000/000" how do I achieve this? Thanks Nevil Amos

as a r noob i am having another problem: i have a big dataframe where each row corresponds to one entry and each column is a field... for instance, i have the column ID and time and many more... Id like to get a dataframe where all IDs are just included once (some users with that ID might have several entries but Id like to kepp only one).. when i use unique I only get a list of the levels (or

...PIPE_7 I have searched through the R-help archives for hints, which have not been successful in answering my question. As a new user to R and programming languages, I truly appreciate your help and thank you for your patience. Thanks in advance for your response, Lanna Jin ----- Lanna Jin lannajin at gmail.com 510-898-8525 -- View this message in context: http://n4.nabble.com/nested-looping-functions-and-dataframes-tp1595166p1595166.html Sent from the R help mailing list archive at Nabble.com.

Hi all, So let's say I have a matrix, mdat and I only know the index number. How do I retrieve the column and row names? For example, > mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("C.1", "C.2", "C.3"))) > mdat[4] [1] 12 >

...differently (in the second image the individual plots are half the height of in the first image). How can I fix this? It would be nice to create a graphic with all of the plots stacked on top of each other with the same axis dimensions and ranges. Thanks for your help in advance! -- Lanna Jin lannajin@gmail.com 510-898-8525 [[alternative HTML version deleted]]

Dear group, I am losing my mind with a simple question. Sorry if obvious, but I maybe start to be confused after days and days of reading documentations. Df : df <- structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class = "factor", .Label = "w")), .Names = c("a", "b", "c"), row.names = c(NA, -3L), class =

Hi guys, I have a matrix with values varying from approximately -0.7 to 0.33 that I want to create a heatmap/levelplot with. When I execute the levelplot function for my matrix, I end up getting colors that are adjusted to the max and min rather than around 0. In other words, ideally I would like to have a color ramp that goes from red (negative number), to white (0), to blue (positive);

Hey all, I feel like the solution to this problem should be relatively simple, but for some reason I can't find answers or come up with my own solution. Given the dataframe: (SpA and SpB not important, want to look at distribution of cooccurance for each year) Year SpA SpB Coocc 2000 0 2000 2 2000 1 2001 8 2001 2 2001 0 2001 0 2002 1 2002 2 How can I apply different functions to

...option N? -- View this message in context: http://r.789695.n4.nabble.com/Show-number-at-each-bar-in-barchart-tp2125438p2125438.html Sent from the R help mailing list archive at Nabble.com. ------------------------------ Message: 16 Date: Tue, 4 May 2010 06:02:29 -0700 (PDT) From: Lanna Jin <lannajin at gmail.com> To: r-help at r-project.org Subject: Re: [R] How to replace all <NA> values in a data.frame with another ( not 0) value Message-ID: <1272978149379-2125464.post at n4.nabble.com> Content-Type: text/plain; charset=us-ascii Try: "x[which(is.na(x)),] <- 000/000&q...

Hello All! I am trying to plot the frequency of species coocurrance. If given a data set similar like this...(V1="species A", V2="species B", V3="frequency of cooccurance") > data V1 V2 V3 1 A B 0 2 A C 2 3 A D 5 4 B C 0 5 B D 1 6 C D 0 > data1<-as.data.frame(lapply(data,function(x)(rep(x,data$V3)))) > as.data.frame(data1[-1]) >