search for: lancet

Hello, I have placed a package on CRAN about two surveys of mortality in Iraq that were published in the Lancet. http://cran.at.r-project.org/src/contrib/Descriptions/lancet.iraqmortality.html > install.packages("lancet.iraqmortality") ... > library(lancet.iraqmortality) Loading required package: foreign > ?lancet.iraqmortality > vignette("mortality") This is a rough vers...

Hello, I have placed a package on CRAN about two surveys of mortality in Iraq that were published in the Lancet. http://cran.at.r-project.org/src/contrib/Descriptions/lancet.iraqmortality.html > install.packages("lancet.iraqmortality") ... > library(lancet.iraqmortality) Loading required package: foreign > ?lancet.iraqmortality > vignette("mortality") This is a rough vers...

...> I've only heard it called a "Tukey mean difference" plot, (and > Trellis graphics has a function, tmd(), that does it, but no one > knows about it...). Does anyone know who invented it? Martin Bland and Doug Altman introduced it in their very successful 1986 paper in The Lancet (which has become a 'Citation Classic') : Bland JM, Altman DG. Statistical methods for assessing agreement between two methods of clinical measurement. Lancet 1986; i: 307-310. BTW, thanks, Troel, for the R function! Christophe -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-...

...ios and Sample probabilities are easy to calculate from the contingency table, but I would appreciate any help on how to calculate the confidence intervals. Below is a simple example of the test, and the corresponding output with the function mcnemar.test. > xtabs(~PLC50.T1+PLC50.T2,data=LANCET.DAT) PLC50.T2 PLC50.T1 0 1 0 464 22 1 6 1 > mcnemar.test(xtabs(~PLC50.T1+PLC50.T2,data=LANCET.DAT)) McNemar's Chi-squared test with continuity correction data: xtabs(~PLC50.T1 + PLC50.T2, data = LANCET.DAT) McNemar's chi-squared = 8....

Recent news articles concerning an article from The Lancet with fabricated data indicate that in the sample containing some 900 or so patients, more than 200 had the same birthday. I was curious and tried out the p and q birthday functions but pbirthday could not handle 250 coincidences with n = 1000. The calculation of upper prior to using uniroot produ...

I came across a post by Karl Knoblick regarding the modeling of longitudinal data (see https://stat.ethz.ch/pipermail/r-help/2007-May/132137.html). I am often asked by physicians to perform what Karl refers to in his post as option 1: to perform paired t-tests against baseline at each follow up time point (30 days, 90 days, 6 months, etc.). Unlike Karl's example, however, many of the trials

...unOnFunction(Function &F); > public: > static char ID; // Pass identification, replacement for typeid > GVN() : FunctionPass((intptr_t)&ID) { } > ... > Yes, I did. And actually everything was doing fine until I added galib ( Genetic Algorithm library from http://lancet.mit.edu/ga/) to my sourcecode. :-( -Nicole- _______________________________________________________________________ Jetzt neu! Schützen Sie Ihren PC mit McAfee und WEB.DE. 30 Tage kostenlos testen. http://www.pc-sicherheit.web.de/startseite/?mc=022220

Hello, I would like to get a correlation coefficient (R-squared) for my model. I don't know how to calculate it in R. What I've done so far: x<-8.5:32.5 #Vektor x y<-c(NA ,5.88 , 6.95 , 7.2 , 7.66 , 8.02 , 8.44 , 9.06, 9.65, 10.22 , 10.63 ,11.06, 11.37, 11.91 ,12.28, 12.69 ,13.07 , 13.5 , 13.3 ,14.14 , NA , NA , NA , NA , NA) #Vektor y

Hello everyone, I have been using R to do some behavioural economic analysis for my masters thesis, specifically fitting demand curves using nls. E.g. Formula: y ~ c + b * x - a * exp(x) Parameters: Estimate Std. Error t value Pr(>|t|) c -0.445097 0.080823 -5.507 0.005304 ** b -0.777105 0.059528 -13.054 0.000199 *** a 0.011908 0.003886 3.064 0.037495 * --- Signif.

...omments, vigorous and even impolite disagreement is acceptable -- as are private, offlist fusillades. I will not try to defend myself on list, though I will publicly acknowledge any error. Cheers, Bert > Surprisingly, it's mostly the not-so-top papers that cause problems here. > When Lancet, New English or BMJ reject some statistical argument, they have > good reasons. Oh? Data to support this assertion, please. > > Dieter > -- Bert Gunter Genentech Nonclinical Biostatistics (But these are my own views, of course, not that of my organization).

I came across this one: http://www.nysun.com/article/32787 which says that the violent death rate in Iraq (which presumably includes violent deaths from the war) is lower than the violent death rate in major American cities. Does anyone have any insights from statistics on how to interpret this?