Displaying 6 results from an estimated 6 matches for "lamda1".
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lamda
2009 Jul 30
1
lmer() and "$ operator is invalid for atomic vectors"
...=TRUE)
attach(data)
new<-data.frame(lamda, age.o_1, Item.l2_2,Subject)
new
Subject <- factor(Subject)
Age <- factor(age.o_1,levels=c("0","1"),labels=c("young","old"))
Item <- factor(Item.l2_2,levels=c("1","2"),labels=c("lamda1","lamda2"))
new2<-data.frame(lamda, Subject, Age, Item)
new2
new3 <- na.omit(new2)
new3
new4=as.data.frame(new3)
> (lmer.lamda <- lmer(lamda ~ Age*Item + ( 1 | Subject), lamda, data=new4))
Error in family$family : $ operator is invalid for atomic vectors
Here are th...
2023 Aug 25
2
Query on finding root
Sir,
I want to solve the equation Q(u)=mean, where Q(u) represents the quantile
function. Here my Q(u)=(c*u^lamda1)/((1-u)^lamda2), which is the quantile
function of Davies (Power-pareto) distribution. Hence I want to solve ,
*(c*u^lamda1)/((1-u)^lamda2)=28353.7....(Eq.1)*
where lamda1=0.03399381, lamda2=0.1074444 and c=26104.50. When I used the
package 'Davies' and solved Eq 1, I got the answer u=0.39...
2023 Aug 27
1
Query on finding root
On Fri, 25 Aug 2023 22:17:05 +0530
ASHLIN VARKEY <ashlinvarkey at gmail.com> wrote:
> Sir,
Please note that r-help is a mailing list, not a knight! ??
> I want to solve the equation Q(u)=mean, where Q(u) represents the
> quantile function. Here my Q(u)=(c*u^lamda1)/((1-u)^lamda2), which is
> the quantile function of Davies (Power-pareto) distribution. Hence I
> want to solve , *(c*u^lamda1)/((1-u)^lamda2)=28353.7....(Eq.1)*
> where lamda1=0.03399381, lamda2=0.1074444 and c=26104.50. When I used
> the package 'Davies' and solved Eq 1, I g...
2006 Jul 22
1
Why the contrain does not work for selecting a particular range of data?
.... I used two way to do this but the results are different.
1.Way one I use the data for x2=1 and run the program. It works for me. Tthe program is described as below:
function (parameters,y1,x11)
{
p<-parameters[1]
alpha1<-parameters[2]
beta1<-parameters[3]
delta1<-parameters[4]
lamda1<-parameters[5]
mu<-alpha1*((x11)^beta1)*exp(-delta1*(x11^lamda1))
ifelse(y1>0|x11>0,
L<-lgamma(y1+p)+p*(log(p)-log(mu+p))+y1*(log(mu)-log(mu+p))-lfactorial(y1)-lgamma(p)
,Inf)
L
}
This is working for me.
2 Way two: I select the data whose x2=1 in the whole range of dat...
2008 Jan 06
2
how to get residuals in factanal
In R factanal output, I can't find a function to give me residuals e.
I mannually got it by using x -lamda1*f1 -lamda2*f2 - ... -lamdan*fn, but the e
I got are not uncorrelated with all the f's.
What did I do wrong? Please help.
Yijun
____________________________________________________________________________________
Be a better friend, newshound, and
2009 Jul 02
2
constrained optimisation in R.
i want to estimate parameters with maximum likelihood method with contraints (contant numbers).
for example
sum(Ai)=0 and sum(Bi)=0
i have done it without the constraints but i realised that i have to use the contraints.
Without constraints(just a part-not complete):
skellamreg_LL=function(parameters,z,design)
{
n=length(z);
mu=parameters[1];
H=parameters[2];
Apar=parameters[3:10];