search for: lambdaf

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2011 Dec 05
1
finding interpolated values along an empirical parametric curve
....Names = c("lambda", "log.det", "norm.beta"), class = "data.frame", row.names = c("0.000", "0.005", "0.010", "0.020", "0.040", "0.080")) clr <- c("black", rainbow(5, start=.6, end=.1)) lambdaf <- c(expression(~widehat(beta)^OLS), ".005", ".01", ".02", ".04", ".08") op <- par(mar=c(4, 4, 1, 1) + 0.2, xpd=TRUE) with(pd, {plot(norm.beta, log.det, type="b", cex.lab=1.25, pch=16, cex=1.5, col=clr, xlab='shrinkage:...
2011 Nov 29
2
format numbers without leading or trailing 0s
A simple question, but I can't find something to do what I want: Given: a vector of numbers, like lambda <- c(0, 0.005, 0.01, 0.02, 0.04, 0.08) Desired: format them in minimal space for use as plot labels, ie, without leading or tailing 0s. For this example: lambdaf <- c("0", .005", ".01", ".02", ".04", ".08") -- Michael Friendly Email: friendly AT yorku DOT ca Professor, Psychology Dept. York University Voice: 416 736-5115 x66249 Fax: 416 736-5814 4700 Keele Street Web: http://www.datav...
2011 Aug 06
0
ridge regression - covariance matrices of ridge coefficients
...ames(X), colnames(X)) } dimnames(coef) <- list(format(lambda), colnames(X)) result <- list(lambda=lambda, coef=coef, cov=cov, mse=mse, scales=Xscale) class(result) <- "ridge" result } # Test: > lambda <- c(0, 0.005, 0.01, 0.02, 0.04, 0.08) > lambdaf <- c("", ".005", ".01", ".02", ".04", ".08") > lridge <- ridge(longley.y, longley.X, lambda=lambda) > lridge$coef GNP Unemployed Armed.Forces Population Year GNP.deflator 0.000 -3.4471925 -1.827886 -0.69...