search for: kruskal

I am using R 2.0.2 on a WinXP I am trying to get the code of the Kruskal-Wallis test but > kruskal.test function (x, ...) UseMethod("kruskal.test") <environment: namespace:stats> > ls(3) [1] "acf" "acf2AR" "add.scope" .............. [181] "kruskal.test" "ks.test&...

Hello, I think I am right in saying that a 2 sample wilcox.test is equal to a 2 sample kruskal.test and a 2 sample t.test is equal to a 2 sample anova. This is also stated in the ?kruskal.test man page: The Wilcoxon rank sum test (wilcox.test) as the special case for two samples; lm together with anova for performing one-way location analysis under normality assumptions; with Student's...

Hi all, I am performing hundreds of kruskal wallis tests and trying to figure out how to create a file of the p.values I obtain. This is the code I use for the tests: A2<-kruskal.test(X2~treatment) A3<-kruskal.test(X3~treatment) A4<-kruskal.test(X4~treatment) A5<-kruskal.test(X5~treatment) A6<-kruskal.test(X6~treatment)...

Thomas Levine writes: > I submit a couple options for addressing bug 16719: kruskal.test > documentation for formula. > https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=16719 > > disallow-character.diff changes the documentation and error message > to indicate that factors are accepted. > > allow-character.diff changes the kruskal.test functions to convert...

I submit a couple options for addressing bug 16719: kruskal.test documentation for formula. https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=16719 disallow-character.diff changes the documentation and error message to indicate that factors are accepted. allow-character.diff changes the kruskal.test functions to convert character vectors to factors; do...

Hi, I am trying to do a kruskal wallis test on two lists, fVisited and cSN: fVisited[[1]] [1] 0.17097623 0.30376141 0.17577266 0.14951855 0.03959753 0.08096217 0.05744888 0.02196257.... .... cSN[[1]] [1] 0.08557303 0.36477791 0.19601252 0.12981040 0.05351320 0.10385542 0.03539577 0.03106175.... So if I just want to do a test...

Hi, I have got two groups of samples; and for every row, I wish to calculate Kruskal-Wallis' p-value. In the example below, and the stars (****) show where I am struggling to design and put things together. Any help would be appreciated. myFile <- data.frame(Sample_1a = 1:10, Sample_1b = 2:11, Sample_1c = 3:12, Sample_2a=4:13, Sample_2b=7:16, row.names=LETTERS[1:10]) grou...

...ata column (plant.height) and other columns (columns 8 to 57), each with number of levels of different factors. ANOVA test was done and the p-values were extracted as follos: a <- function(x) anova(lm(plant.height ~ x))$"Pr(>F)"[1] r<- apply(g[,8:57],2,a) If I try to do a Kruskal-Wallis test : kw <- function(x) kruskal.test(plant.height ~ x)$"p.value" r.kw <- apply(g[,8:57],2,kw) I get the following error message: Error in kruskal.test.default(c(0.16, 0, 0.007, 0.078, 0, 0.08, 0.19, : all group levels must be finite Why do I get this error ? (the valu...

Hi, ?kruskal.test() ?a<- c(2,4,5,2,7) ?b<- c(2,2,6) ?c<- c(3,7,9,3) ?kruskal.test(list(a,b,c)) # ?#? Kruskal-Wallis rank sum test # #data:? list(a, b, c) #Kruskal-Wallis chi-squared = 2.003, df = 2, p-value = 0.3673 A.K. Hi I need an expression in R to apply a kruskal.test to this data (for example...

...a?? a?? a?? a??? a??? b?? b??? b??? c??? c?? c??? c 2? 4??? 5?? 2??? 7??? 2?? 2??? 6??? 3??? 7?? 9??? 3 3? 3?? 4?? 1???? 6??? 8?? 1??? 3??? 5??? 2??? 6??? 3",sep="",header=FALSE,stringsAsFactors=FALSE) library(reshape) ?dat2<-melt(as.data.frame(t(dat1)),id.var="V1")[,-2] kruskal.test(value~V1,data=dat2) # #??? Kruskal-Wallis rank sum test # #data:? value by V1 #Kruskal-Wallis chi-squared = 1.2888, df = 2, p-value = 0.525 #I guess you wanted for each row: lapply(split(dat2,(seq_len(nrow(dat2))-1)%/%ncol(dat1)+1),function(x) kruskal.test(value~V1,data=x)) #$`1` # #??? Krusk...

Recently, I ran a series of Kruskal-Wallace tests [kruskal.test()] using by() to group by site Output is a list: >Herb.KW Herb.df$ID: 10-1 Kruskal-Wallis rank sum test data: Indicator_Rating by Year Kruskal-Wallis chi-squared = 15.24, df = 7, p-value = 0.03302 --------------------------------------------------------...

Dear R users, I would like to know if there is a way in R to execute a post-hoc test (factor levels comparison, like Tukey for ANOVA) of a non-parametric analysis of variance with kruskal.test() function. I am comparing three different groups. The preliminary analysis using the kruskal-wallis-test show significance, but I still don''t know the relationship and the significance level between each group? Do you have any suggestion? Many thanks in advance! Robert...

Hi there, I am doing multiple comparisons for data that is not normally distributed. For this purpose I tried both functions kruskal{agricolae} and kruskalmc{pgirmess}. It confuses me that these functions do not yield the same results although they are doing the same thing, don't they? Can anyone tell my why this happens and which function I can trust? kruskalmc() tells me that there are no differences between any of the gr...

Hi everyone, I am working on analyzing spectra which requires hundreds of kruskal wallis tests to be performed. Once significant results are found post tests are performed ect. My questions are: how do I perform all these kw tests and save just the pvalues in a table? Is there anyway to have R automatically perform post tests if a result of p<0.05 is found? Currently when...

Hello, Is there like the kruskal wallis test in relation to ANOVA (no restrictions on normallity and variance homogenity) something (in R) for MANOVA? thanks -- Dr.Nicolaas Busscher Universit?t GH Kassel Nordbahnhofstrasse: 1a, D-37213 Witzenhausen Phone: 0049-(0)5542-98-1715, Fax: 0049-(0)5542-98-1713

Hi all, The Kruskal-Wallis test is a generalization of the two-sample Mann-Whitney test to *k* samples. That being the case, the Kruskal-Wallis test with *k*=2 should give an identical p-value to the Mann-Whitney test, should it not? x1<-c(1:5) x2<-c(6,8,9,11) a<-wilcox.test(x1,x2,paired=FALSE) b<-kruska...

Hi I need to test scores from questionnaires ADDQoL by age group by Kruskal test. But he wrote me: kruskal.test (wis1 ~ vekkat) Error in kruskal.test.default (c (-2, -4, 0, -1, -1, -3, 0, -4, 0, -1, 0,: all group levels must be finite Vekkat is as.factor and wis1 is as.nuemric How to remove this error? Please advise me. Thank you [[alternative HTML version deleted]]

Hello, I am running Kruskal-Walis test in R. When I try to save results using write.table it gives me the following error : Error in as.data.frame.default(x[[i]], optional = TRUE, stringsAsFactors = stringsAsFactors) : cannot coerce class "htest" into a data.frame The overall code is as follows : >data_file...

...hed the data I am using. I am trying to look at two things: how moisture content changes over time, and how it changes along the length of a log (bolt). My data is not normal and doesn't become normal after ArcSin or Log transformations. Because the 'Days' has 4 levels, I performed a Kruskal-Wallis (kruskal.test) and got significant results. Same for comparing 'Cookie'. Neither of these have only 2 levels so significance here doesn't really explain it in depth....but everything I'm finding for post hoc with a KW says Mann Whitney. But when I try this (wilcox.test) i...

Hola. Llevo poco tiempo con R y estoy atascado en un problemilla, a ver si podéis ayudarme. Estoy trabajando con una base de datos sobre personalidad en diferentes especies de aves. Esta base tiene datos de más de 7000 individuos y me gustaría crear un bucle mediante el cual realizar un test de Kruskal Wallis por cada especie (quiero ver si los comportamientos son consistentes dentro de cada especie). La base de datos que estoy (llamada birddata) utilizando sigue este modelo: Especie (factor) Audacia (numérico) Numero (factor) Cotorra...