Displaying 10 results from an estimated 10 matches for "kiotoqq".
2013 May 11
3
boxplot with grouped variables
my dataset looked like this in the beginning:
>Daten
V1 V2 V3
1 Dosis Gewicht Geschlecht
2 0 6.62 m
3 0 6.65 m
4 0 5.78 m
5 0 5.63 m
I need box plots for V2 with all combination of V1 and V3, so I deleted the
first row, and tried this:
boxplot(Daten$V2[Daten$V3=="m"])
but it does not work and I
2011 Jan 23
2
how to get variance?
I've got this table:
A B
1 7.8 215
2 6.8 280
3 9.4 356
4 5.2 38
5 8.2 167
6 4.8 127
7 3.7 8
8 6.2 201
9 9.7 346
10 8.1 241
how can I get the variance and covariance of A and B?
--
View this message in context: http://r.789695.n4.nabble.com/how-to-get-variance-tp3232523p3232523.html
Sent from the R help mailing list archive at Nabble.com.
2010 Dec 15
1
problems with mosaic plot
I'm pretty sure that I did everything right, but my R is just not drawing the
mosaicplot that I want, and there is also no error messege, looks like this
right now:
> mosaicplot(arthritis)
> mosaicplot(~ sex + treatment + improved, data = arthritis, color = TRUE)
>
--
View this message in context: http://r.789695.n4.nabble.com/problems-with-mosaic-plot-tp3090128p3090128.html
Sent
2012 Dec 07
1
how to add a column from another dataset with "merge"
kiotoqq wrote
> I want to add a shorter column to my dataset with the function "merge",
> it
> should be filled with NAs wo be as long as the other colums, like this:
>
> id age
> 9 46
> 8 56
> 6 52
> 5 NA
> 4 NA
> 3 NA
> 1 NA
>
> i di...
2013 Nov 23
1
how to melt variable to one variable
I want to make a stacked bar plot with one bar for two variables from my
data "chir", the two variables have about 100 values like no, yes and na. I
want to show how many no, yes and na they both have together with the
stacked bar. I tried to melt these to variables first like this:
melt1=melt(data_chir, measure.vars=c("N1_re", "N2_re"), var="zpd")
but it
2011 Aug 13
2
linear regression
dear R users,
my data looks like this
PM10 Ref UZ JZ WT RH FT WR
1 10.973195 4.338874 nein Winter Dienstag ja nein West
2 6.381684 2.250446 nein Sommer Sonntag nein ja Süd
3 62.586512 66.304869 ja Sommer Sonntag nein nein Ost
4 5.590101 8.526152 ja Sommer Donnerstag nein nein Nord
5 30.925054 16.073091 nein Winter Sonntag nein
2011 Aug 14
2
Central limit theorem
my data looks like this:
PM10 Ref UZ JZ WT RH FT WR
1 10.973195 4.338874 nein Winter Dienstag ja nein West
2 6.381684 2.250446 nein Sommer Sonntag nein ja Süd
3 62.586512 66.304869 ja Sommer Sonntag nein nein Ost
4 5.590101 8.526152 ja Sommer Donnerstag nein nein Nord
5 30.925054 16.073091 nein Winter Sonntag nein nein Ost
6
2011 Jan 06
1
need help for chi-squared test
I've got a dataset which looks like this in the beginning:
cbr dust smoking expo
1 0 0.20 1 5
2 0 0.25 1 4
3 0 0.25 1 8
4 0 0.25 1 4
5 0 0.25 1 4
(till no. 1240, anyway, a huge set)
I have to analyse cbr and smoking, I know it works with chisq.test() for the
whole set, but I only need cbr and smoking, and I
2013 May 12
2
need means on all boxplots, but only half of them got that
I tried to draw a point on all boxplots for their means, I did:
boxplot( Daten$weight~interaction(Daten$Dosis,Daten$sex, drop=TRUE))
means<-tapply( Daten$weight, Daten$Dosis, mean)
points(means, pch=5, col="red", lwd=5)
but only the boxplots for male got that point on them, its really weird
because I don't think that I separated the sex in the codes above
[[alternative HTML
2010 Dec 16
2
How can I draw a line in empirical distribution function?
I've got the graphic with this:
a=c(120,40,75,85,55,75,55,90,90,55,155)
plot(ecdf(a))
How can I draw lines to show the lower quatile and upper quartil?
I only know there is the argument lines(),
but I don't know how to use it
--
View this message in context: http://r.789695.n4.nabble.com/How-can-I-draw-a-line-in-empirical-distribution-function-tp3090675p3090675.html
Sent from the R