search for: kiotoqq

Displaying 10 results from an estimated 10 matches for "kiotoqq".

2013 May 11
3
boxplot with grouped variables
my dataset looked like this in the beginning: >Daten V1 V2 V3 1 Dosis Gewicht Geschlecht 2 0 6.62 m 3 0 6.65 m 4 0 5.78 m 5 0 5.63 m I need box plots for V2 with all combination of V1 and V3, so I deleted the first row, and tried this: boxplot(Daten$V2[Daten$V3=="m"]) but it does not work and I
2011 Jan 23
2
how to get variance?
I've got this table: A B 1 7.8 215 2 6.8 280 3 9.4 356 4 5.2 38 5 8.2 167 6 4.8 127 7 3.7 8 8 6.2 201 9 9.7 346 10 8.1 241 how can I get the variance and covariance of A and B? -- View this message in context: http://r.789695.n4.nabble.com/how-to-get-variance-tp3232523p3232523.html Sent from the R help mailing list archive at Nabble.com.
2010 Dec 15
1
problems with mosaic plot
I'm pretty sure that I did everything right, but my R is just not drawing the mosaicplot that I want, and there is also no error messege, looks like this right now: > mosaicplot(arthritis) > mosaicplot(~ sex + treatment + improved, data = arthritis, color = TRUE) > -- View this message in context: http://r.789695.n4.nabble.com/problems-with-mosaic-plot-tp3090128p3090128.html Sent
2012 Dec 07
1
how to add a column from another dataset with "merge"
kiotoqq wrote > I want to add a shorter column to my dataset with the function "merge", > it > should be filled with NAs wo be as long as the other colums, like this: > > id age > 9 46 > 8 56 > 6 52 > 5 NA > 4 NA > 3 NA > 1 NA > > i di...
2013 Nov 23
1
how to melt variable to one variable
I want to make a stacked bar plot with one bar for two variables from my data "chir", the two variables have about 100 values like no, yes and na. I want to show how many no, yes and na they both have together with the stacked bar. I tried to melt these to variables first like this: melt1=melt(data_chir, measure.vars=c("N1_re", "N2_re"), var="zpd") but it
2011 Aug 13
2
linear regression
dear R users, my data looks like this PM10 Ref UZ JZ WT RH FT WR 1 10.973195 4.338874 nein Winter Dienstag ja nein West 2 6.381684 2.250446 nein Sommer Sonntag nein ja Süd 3 62.586512 66.304869 ja Sommer Sonntag nein nein Ost 4 5.590101 8.526152 ja Sommer Donnerstag nein nein Nord 5 30.925054 16.073091 nein Winter Sonntag nein
2011 Aug 14
2
Central limit theorem
my data looks like this: PM10 Ref UZ JZ WT RH FT WR 1 10.973195 4.338874 nein Winter Dienstag ja nein West 2 6.381684 2.250446 nein Sommer Sonntag nein ja Süd 3 62.586512 66.304869 ja Sommer Sonntag nein nein Ost 4 5.590101 8.526152 ja Sommer Donnerstag nein nein Nord 5 30.925054 16.073091 nein Winter Sonntag nein nein Ost 6
2011 Jan 06
1
need help for chi-squared test
I've got a dataset which looks like this in the beginning: cbr dust smoking expo 1 0 0.20 1 5 2 0 0.25 1 4 3 0 0.25 1 8 4 0 0.25 1 4 5 0 0.25 1 4 (till no. 1240, anyway, a huge set) I have to analyse cbr and smoking, I know it works with chisq.test() for the whole set, but I only need cbr and smoking, and I
2013 May 12
2
need means on all boxplots, but only half of them got that
I tried to draw a point on all boxplots for their means, I did: boxplot( Daten$weight~interaction(Daten$Dosis,Daten$sex, drop=TRUE)) means<-tapply( Daten$weight, Daten$Dosis, mean) points(means, pch=5, col="red", lwd=5) but only the boxplots for male got that point on them, its really weird because I don't think that I separated the sex in the codes above [[alternative HTML
2010 Dec 16
2
How can I draw a line in empirical distribution function?
I've got the graphic with this: a=c(120,40,75,85,55,75,55,90,90,55,155) plot(ecdf(a)) How can I draw lines to show the lower quatile and upper quartil? I only know there is the argument lines(), but I don't know how to use it -- View this message in context: http://r.789695.n4.nabble.com/How-can-I-draw-a-line-in-empirical-distribution-function-tp3090675p3090675.html Sent from the R