search for: kfki

...systctl" from "/services/puppet/common/etc/local/sysctl" on the server. But instead of it, strangely enough an empty /etc/local/systctl directory were created on the client machine. Is it a feature or a misconfiguration on my part? Best regards, Jozsef -- E-mail : kadlec@sunserv.kfki.hu, kadlec@blackhole.kfki.hu PGP key: http://www.kfki.hu/~kadlec/pgp_public_key.txt Address: KFKI Research Institute for Particle and Nuclear Physics H-1525 Budapest 114, POB. 49, Hungary

...the rowSums() in the base package is called, not the S4 generic in the Matrix package. Why is that? Is there any way to work around this problem, without depending on Matrix? I am doing this on R 2.14.0, x86_64-apple-darwin9.8.0. Thank You, Best Regards, Gabor -- Gabor Csardi <csardi at rmki.kfki.hu>? ?? MTA KFKI RMKI

Hi, Given a simple example, test <- matrix(c(0.1, 0.2, 0.1, 0.2, 0.1, 0.1, 0.3, 0.1, 0.1), 3, 3) How to generate row indexes for which their corresponding row values are less than or equal to 0.2 ? For this example, row 2 and 3 are the correct ones. Thanks [[alternative HTML version deleted]]

Hi, I have a simple beginner's question on removing a list of objects. Say I have objects C243.Daily1, C243.Daily2...C243.Daily5 in my workspace. I'd like to remove these without using rm five times. So I write. > a <- list(paste("C243.Daily",sep="",1:5)) > rm(a) Obviously this wouldn't work, as it would only remove the object a. But is there any way

...e is downloaded but not deleted." The old mails of our eudora users contain exactly this flag combination: Status: RO Could the compatibility problem somehow be fixed? Currently our system is pretty unusable for the users :-( Thank you and best regards, Jozsef -- E-mail : kadlec at sunserv.kfki.hu, kadlec at blackhole.kfki.hu PGP key: http://www.kfki.hu/~kadlec/pgp_public_key.txt Address: KFKI Research Institute for Particle and Nuclear Physics H-1525 Budapest 114, POB. 49, Hungary

...imapd to dovecot.] That is absolutely devastating, especially for home users behind a modem line. We spent a full week with trying to find a workaround with eudora: no avail. The only solution remained was to revert back to uw-pop3d. :-( Best wishes, Jozsef Kadlecsik -- E-mail : kadlec at sunserv.kfki.hu, kadlec at blackhole.kfki.hu PGP key: http://www.kfki.hu/~kadlec/pgp_public_key.txt Address: KFKI Research Institute for Particle and Nuclear Physics H-1525 Budapest 114, POB. 49, Hungary

Hello I am a relatively new user of R and am struggling to use the 'network' package. I have a correlation matrix (produced using 'cor'), and want to draw a network where each item showing correlation above a threshold (say 0.5) is joined by a green line, and each item showing correlation below a threshold (say -0.5) is joined by a red line. Does anyone have any hints of how to

I have a graph with edge and vertex weights, stored in two data frames: --8<---------------cut here---------------start------------->8--- vertices <- data.frame(vertex=c("a","b","c","d"),weight=c(1,2,1,3)) edges <-

Dear List, i know there are some solutions for this in the archive, but they're not very good for numeric matrices, since they usually convert rows/columns to character strings. Is there an easy way to do $subject for numeric matrices properly, or i need to do it by hand? Thanks, Gabor

Greetings, R-ians: I would like to know which version or R was used to create a given package. I think I remember seeing that topic discussed recently but cannot find it among my notes. Can anyone tell me how to determine which version of R created a package? Thanks. Charles Annis, P.E. <mailto:Charles.Annis@StatisticalEngineering.com> Charles.Annis@StatisticalEngineering.com

How are people upgrading puppet itself on their hosts that run puppetd? Can puppet be used to upgrade to a new puppet package via gem, rpm or some other package provider? How do you handle restarting? Just hoping theres a better way than "ssh and a for loop" or having to have another configuration management system installed.

useR's, Consider: y <- c(20, 25, 30) > m <- matrix(c(0.0,1,NA,0.5,1.25,0.75, 0.5, NA, > NA),byrow=TRUE,nrow=3,ncol=3) > m [,1] [,2] [,3] [1,] 0.0 1.00 NA [2,] 0.5 1.25 0.75 [3,] 0.5 NA NA For each numeric value, I want to replace them with their corresponding y-value. The result should look like (here, each row represents a variable rather than the columns):

I am using the code below to output some network measures: central_social <- data.frame(V(s641_social)$name, indegree_social, outdegree_social, incloseness_social, outcloseness_social, betweenness_social, eigen_social) and I get the following error: Error in Re(z) : non-numeric argument to function I know this has to do with V but I cannot figure out what is wrong. s641-social is a graph

There was a discussion a while ago about adding inheritance to definitions. There is a need for a way to specialize parameters while allowing passing other options. This comes up with remotefile where it would be nice to have a default server location but not specify all the parameters (and their defaults) in the definition. Was there a change to the syntax? Is there a way to accomplish this?

Dear list, Does anyone know how to fit the power law distribution? I have the empirical distribution and would like to check whether it fits power law (with the power estimated from the data). Any hints are appreciated Best regards Galina [[alternative HTML version deleted]]

Hallo, I am running R-2.6. on Windows. I have a code which uses library(convert). Can anyone tell me which package I need to install to run this code. Everytime I receive the error message library (convert) not found. Thanks, Corinna

Using Igraph, I create shortest paths, then convert the matrix into three column vectors - "vertex1", "vertex2", "shortestpath" - as the code below shows. #code for generating shortest path matrix and creating a 3 columns from an igraph graph object "y" y_s<-shortest.paths(y, weights = NULL) y_s <- melt(y_s)[melt(upper.tri(y_s))$value,] #Step 2: this

Hi, I'm working on some social networks and I managed to create the graphs with labels and edges weight, but I would also like to change the size of the vertices according to the age of the persons in the network and the shape according to the gender. Now for the age, I have people with ages between 20 and 78, and I would like to have 4 categories (sizes): 20-35, 36-50, 50-65, >65. I have

Hi to all, does anybody knows whether there is a package to plot those http://www.equine-science.de/temp/graph.jpg graphs. the thickness of the points and/or the lines should be represent the numbers of behaviours With kind regards Knut

Hi, I wish to calculate the characteristic path length of a graph. Is average.path.length(g) in 'igraph' the same as calculating the characteristic path length of the graph? Thanks, Kumar -- View this message in context: http://r.789695.n4.nabble.com/Characteristic-Path-length-calculation-tp3398048p3398048.html Sent from the R help mailing list archive at Nabble.com.