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Hi, I'm new to this list (and R), but my impression is that this question is more appropriate here than R-help. I hope that is right. I'm having several issues with the performance of an R script. Occasionally it crashes with the well-known 'Error: cannot allocate vector of size X' (this past time it was 4.8 Gb). When it doesn't crash, CPU usage frequently drops quite low

Dear R users, I need to run 1000 simulations to find maximum likelihood estimates. I print my output as a vector. However, it is taking too long. I am running 50 simulations at a time and it is taking me 30 minutes. Once I tried to run 200 simulations at once, after 2 hours I stopped it and saw that only about 40 of them are simulated in those 2 hours. Is there any way to make my simulations

This might do it: > lhs=c('a','a','a','b') > rhs=c('a','b','b','b') > > > # function to determine differences > f_diff <- function(l, r){ + t_l <- table(l) + t_r <- table(r) + # compare 'l' to 'r' + sapply(names(t_l), function(x){ + if (is.na(t_r[x])) return(t_l[x])

On Thu, Nov 29, 2018 at 10:51 AM S Ellison <S.Ellison at lgcgroup.com> wrote: > > > When trying out some variations with `[.data.frame` I noticed some (to me) > > odd behaviour, > > Not just in 'myfun' ... > > plot(x=1:10, y=) > plot(x=1:10, y=, 10:1) > > In both cases, 'y=' is ignored. In the first, the plot is for y=NULL (so not

Hi, I would appreciate if somebody could help me with following calculation. I have a dataframe, by 10 minutes time, for mostly one year data. This is small example: > dput(test) structure(list(jul = structure(c(14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655, 14655), origin = structure(0, class = "Date")), time =

Hello I have the following problem : group the lines of a dataframe when no information change (Matricule, Nom, Sexe, DateNaissance, Contrat, Pays) and when the value of Debut of lines i = value Fin of lines i-1 I can obtain it with a do loop. Is it possible to avoid the loop ? The dataframe initial is df1 dput(df1) structure(list(Matricule = c(1L, 1L, 1L, 6L, 6L, 6L, 6L, 6L, 6L, 8L, 8L, 8L,