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Hi is anybody aware of a function to calculate a the median for specified columns in a dataframe or matrix - so analogous to rowMeans? Thanks Max --

Hi I have been trawling the web, FAQs, and R manuals for help on the following issue, but have failed and was wondering if anyone has a solution to the following problem: After having installed R 2.6.2 for Windows (binary), I tried to install various packages. Every time I try loading a package (any package) via the built-in menu, I run into the following error message. >

I have a very basic question about limma. Assume I have experiments from 3 or more RNA sources in a reference design. It is easy to define individual contrasts but I want to specify a contrast matrix that tests for significant differences among ALL the different RNA sources (i.e. the analogous thing to a simple One-Way ANOVA). How can I do that? Thanks! Max --

Hi in dataframe I want to subtract the "next" value in the list from the former one to get this: name var1 output a 9 506 b 515 512 c 1027 453 so I subtract: table$var1[2]-table$var1[1] and write it into table$output[1] etc.. I did this with: for (i in 1:(length(table$var1)){ table$output[i] <- table$var1[i+1]-table$var1[i] } it works

I have a file named "test.csv" with the following 3 lines: %y-%m-%d;VALUE 1999-01-01;100 2000-12-31;999 > read.table("test.csv", header = TRUE, sep = ";") delivers: X.y..m..d VALUE 1 1999-01-01 100 2 2000-12-31 999 I would like to see the following ... %y-%m-%d VALUE 1 1999-01-01 100 2 2000-12-31 999 Note, >