search for: katzner

Displaying 5 results from an estimated 5 matches for "katzner".

2009 Aug 19
2
Contrasts within ANOVA frame (Repost)
Would like to try my luck to see if I can catch your eyes. I was trying to do some contrasts within ANOVA. I searched the archive and found a clue posted by Steffen Katzner ( http://tolstoy.newcastle.edu.au/R/help/06/01/19385.html) I have three levels for a factor names "StdLot" and want to make three comparisons, 1 vs 2, 1 vs 3 and 2 vs 3. First, contrasts(d3$StdLot,3)<-matrix(c(1,-1, 0,0,1,-1,1,0,-1),3,3) #d3 is the data set. set up the contrast mat...
2004 Aug 21
1
relative frequencies for hist()
I have problems getting a histogram with relative frequencies on the y-axis. Here is an example data set: > a <- c(4.626, 4.627, 4.627, 4.628, 4.629, 4.629, 4.630, 4.631, 4.632, 4.632) > d = hist(a,freq=F) > d$density [1] 299.9999 100.0000 200.0000 100.0000 100.0000 200.0000 The obtained densities are given by counts/(total n * bin width), with bin width being
2009 Aug 11
0
Contrasts within ANOVA frame
Dear all, I was trying to do some contrasts within ANOVA. I searched the archive and found a clue posted by Steffen Katzner ( http://tolstoy.newcastle.edu.au/R/help/06/01/19385.html) I have three levels for a factor names "StdLot". I just want to make three comparisons, 1 vs 2, 1 vs 3 and 2 vs 3. First, contrasts(d3$StdLot,3)<-matrix(c(1,-1, 0,0,1,-1,1,0,-1),3,3) #d3 is the data set. set up the contrast...
2006 Jan 22
0
Error in 1:object$rank : NA/NaN argument
can anybody help with the following error message: Error in 1:object$rank : NA/NaN argument I get it with comparisons of single means in an ANOVA. Example data below. Thanks, Steffen seven subjects participated in each of 6 conditions (intervals). > subject = factor(rep(c(1:7), each = 6)) > interval = factor(rep(c(1:6), 7)) and here is the dependent variable: > dv = c(3.3868,
2006 Jan 18
1
Within-Subjects ANOVA & comparisons of individual means
I am having problems with comparing individual means in a within-subjects ANOVA. From my understanding, TukeyHSD is not appropriate in this context. So I am trying to compute contrasts, as follows: seven subjects participated in each of 6 conditions (intervals). > subject = factor(rep(c(1:7), each = 6)) > interval = factor(rep(c(1:6), 7)) and here is the dependent variable: > dv