Displaying 1 result from an estimated 1 matches for "k1y2g".
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k12
2009 Oct 19
2
Using grep to determine value of last letter...
...500, 2000, 1450)
Exterior<-c("Brick", "Stone", "Siding", "Brick", "Siding")
SubdivisionHouses<-data.frame(BuildYear, SqrFootage, Exterior)
Year<-c(1980, 1985, 1975, 1990, 1977, 1986)
Codes<-c("G2G1L", "G5L1F", "K1Y2G", "G4B1B", "K1N3B", "K3M4X")
BuildingCodes<-data.frame(Year, Codes)
HousesWithCodes<-merge(SubdivisionHouses, BuildingCodes, by.x="BuildYear", by.y="Year")