search for: juryef

Hi, I have been trying many of the suggested options to place a legend outside plotting area, including something like this: par(xpd=T, oma=par()$oma+c(4.5,0,1.5,0),mar=par()$mar+c(1,0,1,0) But the aspect of the four plots gets compromised when I change the margin settings. I cannot use mtext because I need to use colors for the text. I tried layout, but wouldn't let me include

Hi, I have a vector in a data frame that looks something like this: day<-c('Day -1','Day 6','Day 10') This vector specifies the order in which several panel will appear in a lattice plots. But the order in which such plots will appear will be the following: Day -1, Day 10, Day 6. Which makes sense, but I cannot name the Days like this: Day -01,Day 10, Day 06,

Dear R experts, I am sorry for sending this email again. I would imagine yesterday and maybe today, have been very busy days with the release of R v 2.7.0. I join all the R users who are very gratful for your contant work and efforts, specially knowing that you are doing this for the sake of science, without gettig any compensation for that. Having written that, I decided to send the

Hi, I need to run a script under the variable (that comes from a csv file) that is assigned to another variable. This is very a simplified version of what I want to do: data<-read.csv('name.csv') names(data)<-("VA","VB","VC") v<-VA mn(v) Thank you in advance, Judith

...day = c(-1, -1, -1, 2, 2), k = c(566, 680, 773, 298, 273)) transform(DF, percent = 100 * k / k[match(id, id)] - 100) Also, please use meaningful subject headings so that future persons having the same problem can more easily locate it in the archive. On Nov 30, 2007 8:44 PM, Judith Flores <juryef at yahoo.com> wrote: > Sorry about that, it was sent by accident. > > I have a data frame that looks something like this: > > id day k > 56 -1 566 > 63 -1 680 > 73 -1 773 > 56 2 298 > 63 2 273 > > Of course, it is a very simplified ver...

Hello, I need to add some text in the upper left position, outside a lattice plot. xyplot(x~y) ltext(locator(1), label='My text') doesn't work. I would appreciate any help. Tahnk you, Judith ____________________________________________________________________________________ Be a better friend, newshound, and

Hi there, I need to save a series of lattice plots as a PDF, this is my code so far: windows(height=8,width=6) plot.new() library('grid') lattice.options(layout.heights=list(top.padding=list(x=0.15, units="inches"))) print(plot1, split=c(1,1,2,3), more=TRUE) print(plot2, split=c(1,2,2,3), more=TRUE) print(plot3, split=c(1,3,2,3), more=TRUE) print(plot4, split=c(2,1,2,3),

Hi, Is there an analog function of textplot in the lattice package? I need to add a data frame to a lattice plot. I work in a Windows environment and I am using R v 2.6.1 Thank you, Judith ____________________________________________________________________________________ Be a better friend, newshound, and

Dear R-experts, I need to replace the values of a vector(tx) with a word ('Vehicle') when the value of the vector contains the word 'vehicle'. Sometimes, the value could be 'MCT vehicle', or 'control-vehicle', etc. I tried gsub like this treatment<-gsub('vehicle','Vehicle', tx, ignore.case=T) But then I end up with values like 'MCT

Hello dear R-community, I have been trying to figure out a way to generate histograms of a numeric variable observed in different entities ('individual' below). Each one of this entities is classified as "A" or "B" (according to the pseudo-code below): variable<-sample(rep(1:10,10)) individual<-rep(1:10, length(variable))

Hi, I have a csv file with empty values, when I apply the different functions (mean, std, etc.) I create a new data frame, the empty values generate Inf and -Inf values. How can I remove those Inf and -Inf values from the new data frame? I already specified na.rm in the mean and std functions, but the values are still there. Thank you, Judith

Sorry, I just realized I didn't type in the correct names of the variables I am working with, this is how it should be: plot(1,1,type="n") for (i in summ$tx) { points(summ$timep[summ$tx==i],summ$mn[summ$tx==i]) lines(summ$timep[summ$tx==i],summ$mn[summ$tx==i]) } Thank you, Judith ____________________________________________________________________________________

Hi there, I found one reference to add a reactangle behind a plot using plot(...,add=T), I tried this but didn't obtain the desired result. If a I have the following code: plot(x,y) rect(xleft, ybottom, xright,ytop,col='green) The rectangle appear on top of the plot. Any help will be greatly appreciated, Judith

Sorry about that, it was sent by accident. I have a data frame that looks something like this: id day k 56 -1 566 63 -1 680 73 -1 773 56 2 298 63 2 273 Of course, it is a very simplified version of the real data frame I am working on. I need to add another column that would represent a percent change in k from day -1, by id. I put only two ids at day 2 to

Hello R-users,    I have a data frame whose names of columns I don't know a priori, but the user of my code will know them. The user is supposed to save the name of the column that will need some reordering of the levels of the factor later on. The name of the column will be saved in an object called: variab the data frame is called df. If I try to the do following:

Hello R-community, I want to generate stacked density plots in lattice. My data consist of a numeric variable ('pid') that is measured in different individuals ('id'), which can be divided in two types ('type') and the measurements were repeated a different time points ('day'). I read in the Lattice book that this can be done using the 'flowViz'

Hi all, I I need to manipulate the x axis in a stripchart. I will use one of the data sets included in R to explain what I need to do. attach(ToothGrowth) stripchart(len[supp=='VC']~dose[supp=='VC'], vertical=TRUE, group.names=c('A','A','A')) stripchart(len[supp=='OJ']~dose[supp=='OJ'], add=TRUE, vertical=TRUE, at=c(1:3)+.1,

Hi Deepayan and everyone, I need to add a common legend to a group of latice graphs, I have tried different ways using viewport and grid.draw without success. Here is what I have: plot.new() library(grid) library('IDPmisc') print(plot1, split=c(1,1,2,4), more=TRUE) print(plot4, split=c(2,1,2,4), more=TRUE) print(plot2, split=c(1,2,2,4), more=TRUE) print(plot5, split=c(2,2,2,4),

Sorry, I hit the send botton by accident. Here is my code so far: dat<-read.csv('myfile.csv', na.strings="") dat[is.na(dat]<-'N' But it doesn't replace the <NA> for the letter 'N'. I am using R v 2/7/0, running it under Windows XP. Thank you, Judith

Dear R-helpers, I am sorry for asking something I know has been asked before, I have tried different combinations in the strip function without success... I am using version 2.5.1 and work on a PC. I have barcharts generated from the following formula: barchart(y1+y2+y3~x | g) I need to change the names of the variables y1,y2 or y3 that currently appear in the strips, I have two