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Hi, How i can convert a array in to data.frame structure? For example, vinteesete<-array(c(1,0,6,4,22,29,11,7,6,2,8,7,21,25,5,6,1,0,11,6,14,24,13,10,2,2,15,13,14,17,9,8,1,2,16,9,14,23,9,6,6,2,17,13,10,20,7,5), dim=c(2,4,6), dimnames=list(grupo=c("I","II"), opiniao=c("Ma","Regular","Boa","MBoa",),

..._, _ | | | | | / \_/ | / | |/ | | | \_|/\__/ |_/\_/|/|__/ | | |_/o /| /| \| \| -- +----------------------------------------------------------------------+ | Jorge Magalh?es Email: jmagalhaes at eng.uminho.pt | | Departamento de Eng Mecanica Telem?vel: 966172200 | | University of Minho Fax: + 351 253 516007 | | Guimaraes Phone: + 351 276 333008 | | Portugal Email: jorgemagalhaes...

...ue of the correlation coefficient for the linear regression of the variable i with the variable j. i=1...4, j=1...4 Xi vs Xj indicate a plot(Xi,Xj). Have a nice day Jorge. -- +----------------------------------------------------------------------+ | Jorge Magalh?es Email: jmagalhaes at eng.uminho.pt | | Departamento de Eng. Mec?nica Phone: + 351 253 510220 | | Universidade do Minho Fax: + 351 253 516007 | | Campus de Azur?m Phone: + 351 276 333008 | | 4810 Guimar?es, Portugal Email: mop41059 at mai...

..._out and yellow=Tmax_out > coplot(Qu1 ~ Qu2 | Ku1*Ph1, data = dados, pch = 3, col = cores) but i need the legend!!! Have a nice day Best regards Jorge ****************************** Jorge M. A. Magalhaes Quinta do Calv?rio bloco 14, 2? Direito tr?s 5400 Chaves tel: +351 76 333008 e-mail: jmagalhaes at eng.uminho.pt -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-hel...

...e: *** [R] Error 1 ############### end error message My question: I need upgrade my suse version from 6.0 to 6.4 for install R-1.1.0 in my linux box? Thanks in advance Jorge -- +----------------------------------------------------------------------+ | Jorge Magalh?es Email: jmagalhaes at eng.uminho.pt | | Quinta do Calv?rio, bloco 14 Telem?vel: 966172200 | | 2? Direito Tr?s Fax: + 351 253 516007 | | 5400 Chaves Phone: + 351 276 333008 | | Portugal Email: jorgemagalhaes...

How i can perform a Pearson's Chi-squared Test in this data set: | Outcome -----------------+-----------+----------------------------------+ Treatment | Sex | None |Some | Marked | Total -----------------+------------+--------+--------+-------------+ Active | Female | 6 | 5 | 16 | 27

I'm reading a old statistics book "MARVIN J. Karson (1982), Multivariate Statistical Methods, The IOWA State University Press, Iowa". In the chapter XI i can find some information about discrete multivariate analysis. This chapter is restricted to an introduction to log-linear models for analysis of multidimensional contingency tables. For example, in the log-linear model for

Dear Sirs I can't try the package sets because I have a old mac system. Package sets needs R = 2.6. I need to group some variables into a set of new variables defined by a particular modality: Example: my.df = data.frame(var1=c(1,2,2,1,2,2,1,2), var2=c(2,2,1,1,2,2,1,1), var3=c(1,2,2,1,1,1,1,2), var4=c(1,1,1,1,2,1,2,1)) I'm looking for a way to compute set1 and set2? set1 = c(5,4) %

Dear Sirs What is the best aproximation to the standardized normal distribution: necessidade = c("sem necessidade","com necessidade") tipo =c("CE-1", "CE-2", "CE-3") dados=c(20,34,44,69,9,3) Tabela =cbind(expand.grid(list(Necessidade=necessidade, Tipo=tipo)), count=dados) Tabela.array=tapply(Tabela$count, Tabela[,1:2], sum) ni =

Dear R-users I need to convert a matrix with three columns in a new array with multiple columns. For example, oldmatrix 1 4 5 1 54 52 1 9 43 2 32 5 2 54 6 2 76 6 3 54 54 3 543 7 3 54 6 newmatrix 5 5 54 52 6 7 43 6 6 if the first column have a new value then add a column to the new matrix and the new[i,j] <- old[,3][i] I write this code, but my initial matrix is very