Displaying 5 results from an estimated 5 matches for "jinsong_zh".
2004 Aug 03
4
How to select a whole column? Thanks!
...0 0 -0.009 -0.012 -0.015 -0.018
I mean how to select the first four columns.
Thank you very much for your consideration on this matter.
Best wishes,
Jinsong
=====
(Mr.) Jinsong Zhao
Ph.D. Candidate
School of the Environment
Nanjing University
22 Hankou Road, Nanjing 210093
P.R. China
E-mail: jinsong_zh at yahoo.com
2004 Feb 04
1
center or scale before analyzing using pls.pcr
...be scaled. If the dependent variable is
scaled, how I give a prediction to the real data?
I appreciate for any suggestions and comments.
Best regards,
Jinsong
=====
(Mr.) Jinsong Zhao
Ph.D. Candidate
School of the Environment
Nanjing University
22 Hankou Road, Nanjing 210093
P.R. China
E-mail: jinsong_zh at yahoo.com
2004 Aug 04
1
What's ``impres''?
...cat("blah blah blah \n")
Would someone here like to tell me what's the counterpart in R to
impres in S+?
Thanks in advance!
Best wishes,
Jinsong
=====
(Mr.) Jinsong Zhao
Ph.D. Candidate
School of the Environment
Nanjing University
22 Hankou Road, Nanjing 210093
P.R. China
E-mail: jinsong_zh at yahoo.com
2004 Feb 01
5
Stepwise regression and PLS
Dear all,
I am a newcomer to R. I intend to using R to do stepwise regression and
PLS with a data set (a 55x20 matrix, with one dependent and 19
independent variable). Based on the same data set, I have done the same
work using SPSS and SAS. However, there is much difference between the
results obtained by R and SPSS or SAS.
In the case of stepwise, SPSS gave out a model with 4 independent
2004 Feb 06
1
problem to get coefficient from lm()
Dear all,
The following is a example that I run and hope to get a linear model.
However, I find the lm() can not give correct coefficients for the
linear model.
I hope it's just my own mistake. Please help. TIA.
Regards,
Jinsong
> x
[1] 3.760216 3.997288 3.208872 3.985417 3.265704 3.497505 2.923540
3.193937
[9] 3.102787 3.419574 3.169374 2.928510 3.153821 3.100385 3.768770
3.610583