search for: jbarnier

Hi all, I currently work on a survey which contains biographical data stored in a chronological way, ie something like : id year variable 001 2000 0 001 2001 0 001 2002 1 001 2003 0 002 1996 0 002 1997 0 002 1998 1 002 1999 0 002 2000 0 where id is a person identifier, year the year of observation and variable the

Hello, I am trying to draw the biplot of a PCA, but I would like to use another variable of my initial data frame than my "row.names" to assign labels to the points. A part of my R file follows ; "m" is my initial data frame, which has the variable "code" as row.names, and another variable "name" that I'd like to use as labels for the points. >

Hi, I am trying to use ggplot2 graphics with Sweave, but I got problems with transparency support when generating pdf figures, even if I specify a ?pdf.version? argument in Sweave options. More precisely, forcing the pdf version by creating the file manually works : <<fig=FALSE,results=HIDE>>= pdf(version="1.4",file="foo.pdf") ggplot(d,aes(y=t,x=u)) +

Hi all, I recently put a new version of my french introduction to R online. It is more specifically targeted at social sciences students and researchers, but could be interesting for beginners who are not really familiar with statistics and coding. The document is available (in french) in PDF, as well as the Sweave source code, from the following page : http://alea.fr.eu.org/j/intro_R.html

Hi to all, I recently created a small package which contains some simple R functions in order to help students in my research unit to use R. The package is pure R, it passes R CMD check, but it is really designed for internal use and, moreover, it is entirely documented in french. Is it possible to upload and to host this kind of package to CRAN ? Or is it better, as it is quite a private tool

Hi, Excuse me for a so dummy question, but I really can't manage to do this very simple thing : I have a data frame, and I would like to calculate two vectors which contain the sums respectively of the rows and of the columns of the matrix. There is surely a very simple way to do that, but I didn't find it... Many thanks in advance.