search for: janes

Hi. I have a character vector that looks like this: > temp <- c("Company name: The first company General Manager: John Doe I > Managers: John Doe II, John Doe III","Company name: The second company > General Manager: Jane Doe I","Company name: The third company Managers: > Jane Doe II, Jane Doe III") > temp [1] "Company name: The first company

As an R beginner, I feel brain dead today as I can not find the answer to a relatively simple question. Given a array of string values, for example lets say "mary", "bob", "danny", "sue", and "jane". I am trying to determine how to perform a logical test to determine if a variable is an exact match for one of the string values in the array

Hello, a have two matrices of data as below. I would like to add-up the duplicate in terms of pair of names in rows, and then merge the values in the second matrix to the pairs as two new variables x3 and x4. Input ,x1,x2 jane.mike,31,43 jane.steve,32,2 jane.steve,5,3 jim.mike,76,5 jane.steve,4,4 mike.steve,54,7 mike.steve,5,7 jane.mike,7,8 and ,y jane,0.3 jim,0.4 mike,0.1 carl,0.5 john,0.9

Hello, I am new to Dovecot and trying to setup on my Fedora Core 1 mail servers (actually migrating from uw to dovecot ;-) ). In my setup I use pam to authenticate virtual users. All the usernames include @domainname in their usernames like 'jane at somevhost.com'. Now path to user's home and INBOX includes /home/vhosts/<domainname>/home/<username>. I have added following

Hi all, for the data below I would like to 1. generate a dummy variable for each group "gr" of the same composition by people, then save each portion in a separate file, 2. compute the frequency of "1"'s in "x" for each person by group "gr". So, "mike" will have freq=2/3, as he has two "1" and one "0" in 3 groups.

The manual at http://wiki2.dovecot.org/Tools/Doveadm/Deduplicate tells how to estimate what will be expunged: > doveadm -f table fetch -u jane 'guid uid' mailbox a_Box | sort I wanted to learn the subjects: > doveadm -f table fetch -u jane 'guid hdr.Subject' mailbox a_Box In the output, long lines will be broken up, continuation lines starting with a blank (mostly),

Hello, I am having trouble getting the output from the tapply function formatted so that it can be made into a nice table. Below is my question written in R code. Does anyone have any suggestions? Thank you. Geoff #Input the data; name <- c('Tom', 'Tom', 'Jane', 'Jane', 'Enzo', 'Enzo', 'Mary', 'Mary'); year <- c(2008, 2009,

Hi, I'm trying to do some basic social network analysis with igraph in R, but I'm new to R and haven't been able to find documentation on a couple basic things: I want to run igraph's community detection algorithms on a couple thousand small graphs but don't know how to automate igraph looking at multiple graphs described in a single csv file. My data look like something in

Hi Can anyone help with the technique of obtaining leverages from a conditional logistic regression model? The code lm.influence does not seem to work for this data. Thanks Jane Murray

Hi, FrameBuffer has the option "fbcon=rotate:1". Could a similar functionality be implemented in the video driver (VBE?) that is used by Syslinux? Is it legal to copy that code from the FBCon portion into the Syslinux video driver portion? If so, where should I start looking? Thanks for all your help. SS On Fri, May 15, 2020 at 7:15 AM Jane Todoroski <jane.todoroski at

Dear all, Lets say I have the following data frame: > df1 <- data.frame(Show=c('Star Trek', 'Babylon 5', 'Dr Who'), Size=c(0.7, 0.0, 0.701), Date=as.Date(c('2007-08-03', '2007-08-03', '2007-08-03'), format='%Y-%m-%d')) > df2 <- data.frame(Show=c('Star Trek', 'Dr Who', 'Torchwood'), Size=c(0.8, 0.85,

Suppose I have the following list: a <- strsplit(c("John;Smith", "Jane;Doe", "koda", "gunner"), ";") I want to get to these two vectors without looping... firstNames: c("John", "Jane", "koda", "gunner") lastNames: c("Jane", "Doe", NA, NA) Thanks cn [[alternative HTML

Hello, As per wiki instructions, I tried to enable zlib compression of mails by adding/modifying the following snippets of configuration: plugin { zlib_save_level = 6 zlib_save = gz } and protocol imap { mail_plugins = fts fts_squat autocreate zlib imap_zlib imap_id_log = * } I am using dbox format and delivering the mails via dovecot deliver, however mails don't seem

On 13/06/15 16:33, Jonathan Hunter wrote: > Hi buhorojo, > > I *think* I have a stable system for the moment... so thank you :-) > > On 13 June 2015 at 12:50, buhorojo <buhorojo.lcb at gmail.com> wrote: >>> I now set in smb.conf: >>> >>> server services = -dns +winbind -winbindd >>> >>> I stopped samba, then removed

I recently switched from using Redhat Linux 9 to SuSE 9.2 Pro and am having problems with an auto mounted share served from a Macintosh running Mac OS 10.3.6. I can read from the share without problems. However, writing to it is a different story. All the files/folders on the share are owned by janee in the group janee and have rw owner and group permissions. I've tried playing with the

On Mon, 19 Jun 2017 14:46:34 +0200 Viktor Trojanovic <viktor at troja.ch> wrote: > On 19 June 2017 at 14:20, lingpanda101 via samba > <samba at lists.samba.org> wrote: > > > On 6/19/2017 7:51 AM, Viktor Trojanovic via samba wrote: > > > >> That's correct, I don't have "Unix Attributes" but through the > >> advanced view I have

Hi all, rmvnorm()can be used to generate the random numbers from a multivariate normal distribution with specified means and covariance matrix, but i want to specify the correlation matrix instead of covariance matrix for the multivariate normal distribution. Does anybody know how to generate the random numbers from a multivariate normal distribution with specified correlation matrix? What about

Despite a long search on the archives, I couldn't find how to do this. Thanks in advance for what is likely a simple issue. I have a data set where the first column is name (i.e., 'Joe Smith', 'Jane Doe', etc). The following columns are data associated with that person. I have many people with multiple rows. What I want is to get a new data frame out with only the people who

Thanks. isFreeCall() works well but for %call2 = call i32 bitcast (i32 (...)* @free to i32 (i8*)*)(i8* %call1) nounwind, !dbg !16 So I tried to figure out when the above instruction occurred. When <stdlib.h> is included, free(buf2R1); turn into call void @free(i8* %call1) nounwind, !dbg !16 when I forget to include <stdlib.h>, free(buf2R1); turn into %call2 = call i32 bitcast (i32

Tim: Are Ron & Jane of Santa Barbara your parents? We are good friends from Santa Barbara and my wife wants to send her a birthday card in Kansas City but we don''t have your address. Allan & Joyce Anderson -------------- next part -------------- An HTML attachment was scrubbed... URL: