search for: jabezwuk

Dear all, I'm trying to process a log file which logs the date, the username and the computer number accessed. The table looks like this: >table.users          Date UserName Machine 1  2008-11-25     John     641 2  2008-11-25    Clive     611 3  2008-11-25   Jeremy     641 4  2008-11-25     Walt     722 5  2008-11-25     Tony     645 6  2008-11-26     Tony     645 7  2008-11-26    

...Control_3 probe~B01R09C02 464 836 508 53 5 MM0289~RFU:11810.15 probe~B29R13C06 99 544 607 984 6 MM0289~RFU:9238.41 probe~B29R13C05 605 603 862 575 7 MM16597~RFU:36765.38 probe~B44R15C20 700 923 219 582 8 MM16597~RFU:41258.94 probe~B44R15C19 132 777 497 995 --- On Thu, 1/12/11, Jabez Wilson <jabezwuk@yahoo.co.uk> wrote: From: Jabez Wilson <jabezwuk@yahoo.co.uk> Subject: calculate mean of multiple rows in a data frame To: "R-Help" <r-help@stat.math.ethz.ch> Date: Thursday, 1 December, 2011, 20:45 Dear all, I have a data frame (DF) in the following format:...

Dear R Help, I have a set of data of heights of trees described by area that they are in. The areas are numerical (0 to 7). ht area 1 320 3 2 410 4 3 230 2 4 360 3 5 126 1 6 280 2 7 260 2 8 280 2 9 280 2 10 260 2 ....... 180 450 4 181 90 1 182 120 1 183 440 4 184 210 2 185 330 3 186 210 2 187 100 1 188 0 0 I want to convert the

Dear list, I have read an excel table into R using read.table() and headers=T. The table is 7 columns of figures. Is there any way to gain access to the header information? Say the table headers are Mon, Tue etc I can get to the data with myTable$Tue, but how do I get the headers themselves. TIA Jab [[alternative HTML version deleted]]

...first part. The second part I do not understand. All I get is "3" "3". Presumably this is the factor that you refer to. Is there no simple way of extracting the text alone ----- Forwarded Message ---- From: Peter Alspach <PAlspach@hortresearch.co.nz> To: Jabez Wilson <jabezwuk@yahoo.co.uk> Sent: Tuesday, 7 November, 2006 7:46:02 PM Subject: RE: [R] data frames re-ordering and naming columns Jabez > -----Original Message----- > From: r-help-bounces@stat.math.ethz.ch > [mailto:r-help-bounces@stat.math.ethz.ch] On Behalf Of Jabez Wilson > Sent: Wednesday,...

You've spotted it! table(df$area) 0 1 2 3 4 5 7 21 27 71 46 19 3 1 There are no values in area 6. Thank you very much. Jabez ----- Original Message ---- From: Petr PIKAL <petr.pikal@precheza.cz> To: Jabez Wilson <jabezwuk@yahoo.co.uk> Cc: R-Help <r-help@stat.math.ethz.ch> Sent: Friday, 10 August, 2007 1:02:21 PM Subject: Odp: [R] having problems with factor() Hi r-help-bounces@stat.math.ethz.ch napsal dne 10.08.2007 13:41:53: > Dear R Help, > I have a set of data of heights of trees described by ar...

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I'd like to "step" through 24 histograms by using the return or click button option, as shown in the demo(graphics) demonstration. I've searched for "interactive graphics", and "waiting for page change" in R documentation but with no result. I'm sure that this is a relatively straightforward procedure. Can anyone point me to the correct solution?   Jabez

Dear all, please help with what must be a straightforward question which I can't answer. I add a column of my dataframe as factor of an existing column e.g. df[,5] <- factor(df[,2]) and can test that it is by is.factor() but if I did not know in advance what "types" the columns were, is there a function to tell me what they are. i.e. instead of

Hi, I've read in a csv file (test.csv) which gives me the following table: Hin1 Hin2 Hin3 Hin4 Hin5 Hin6 HAI1 9534.83 4001.74 157.16 3736.93 484.60 59.25 HAI2 13272.48 1519.88 36.35 33.64 46.68 82.11 HAI3 12587.71 5686.94 656.62 572.29 351.60 136.91 HAI4 15240.81 10031.57 426.73 275.29 561.30 302.38 HAI5 15878.32 10517.14 18.93 22.00 16.91

...posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > > > ------------------------------ > > Message: 11 > Date: Fri, 10 Aug 2007 11:41:53 +0000 (GMT) > From: Jabez Wilson <jabezwuk@yahoo.co.uk> > Subject: [R] having problems with factor() > To: R-Help <r-help@stat.math.ethz.ch> > Message-ID: <266689.93457.qm@web27410.mail.ukl.yahoo.com> > Content-Type: text/plain > > Dear R Help, > I have a set of data of heights of trees described by area...

Dear R-Help, I have an array 1260x1260, upper triangle consisting of numbers between 0 and 100, and lower triangle all NA. I can extract the index of those values say above 99 using the following code: which(myArray>=99 , ind.arr=T) which returns: row col 5475 252 253 45423 764 765 46902 777 778 34146 611 962 50681 1220 1221 Now I would like to if poss print the actual value

>Date: Thu, 6 Mar 2008 06:46:07 -0800 (PST) >From: Keizer_71 <christophe.lo@gmail.com> >Subject: [R] Statistical Questions: finding differentially expressed >genes >To: r-help@r-project.org >Message-ID: <15873163.post@talk.nabble.com> >Content-Type: text/plain; charset=us-ascii >Hi Everyone, >I am trying to find a way to do this in excel to tell me which

Dear all, I have a data frame (DF) in the following format: NAME ID a b c d 1 Control_1 probe~B01R01C01 381 213 345 653 2 Control_2 probe~B01R01C02 574 629 563 783 3 Control_1 probe~B01R09C01 673 511 521 967 4 Control_3 probe~B01R09C02 53 809 999 50 5 MM0289~RFU:11810.15 probe~B29R13C06 681 34 115 587 6 MM0289~RFU:9238.41 probe~B29R13C05 784 443 20 784 7 MM16597~RFU:36765.38

Dear R users, please can you help me understand the behaviour of abline using function lm. I'm trying to learn linearity over groups. So I make three groups with 10 values each: test=data.frame(cbind( l=c(rnorm(10,0,30),rnorm(10,100,30),rnorm(10,200,30)), t = c(rep(0,10), rep(1,10), rep(2,10)) )) when I do: plot(test$l~test$t) abline(lm(test$l~test$t)) the abline is a straight line

Dear R help, I have a data frame column in which I would like to replace some of the numbers dependent on their value. data frame = zz AveExpr t P.Value FC 7.481964 7.323950 1.778503e-04 2.218760 7.585783 12.233056 6.679776e-06 2.155867 6.953215 6.996525 2.353705e-04 1.685733 7.647513 8.099859 9.512639e-05 1.674742 7.285446 7.558675 1.463732e-04 1.584071

Hi, I am trying to reconcile anova table in R (summary(lm)) with individual t.test. datafilename="http://personality-project.org/R/datasets/R.appendix1.data" data.ex1=read.table(datafilename,header=T) #read the data into a table summary(lm(Alertness~Dosage,data=data.ex1)) gives: Call: lm(formula = Alertness ~ Dosage, data = data.ex1) Residuals:    Min     1Q Median     3Q    Max

Dear all, I am perplexed when trying to get the same results using pairwise.t.test and t.test. I'm using examples in the ISwR library, >attach(red.cell.folate) I can get the same result for pairwise.t.test and t.test when I set the variances to be non-equal, but not when they are assumed to be equal. Can anyone explain the differences, or what I'm doing wrong? Here's an example