search for: iv441

...} } On Wed, Mar 7, 2012 at 4:04 PM, Ryan Taylor <ryta1203 at gmail.com> wrote: > I have attached a case of what I am trying to do, I'm pretty sure I'm just > missing some simple API call. In the cfg you can see that although Im > setting "lsr.iv441" as "lsr.iv44" from for.body.387.i it's not propagating > that through the block or graph. > > > On Wed, Mar 7, 2012 at 12:03 PM, Ryan Taylor <ryta1203 at gmail.com> wrote: > >> I am splitting a one BB loop into two BB. >> >> Basically, the...

I have attached a case of what I am trying to do, I'm pretty sure I'm just missing some simple API call. In the cfg you can see that although Im setting "lsr.iv441" as "lsr.iv44" from for.body.387.i it's not propagating that through the block or graph. On Wed, Mar 7, 2012 at 12:03 PM, Ryan Taylor <ryta1203 at gmail.com> wrote: > I am splitting a one BB loop into two BB. > > Basically, the one loop BB has 3 incoming values,...

...} > > On Wed, Mar 7, 2012 at 4:04 PM, Ryan Taylor <ryta1203 at gmail.com> wrote: > >> I have attached a case of what I am trying to do, I'm pretty sure I'm >> just missing some simple API call. In the cfg you can see that although Im >> setting "lsr.iv441" as "lsr.iv44" from for.body.387.i it's not propagating >> that through the block or graph. >> >> >> On Wed, Mar 7, 2012 at 12:03 PM, Ryan Taylor <ryta1203 at gmail.com> wrote: >> >>> I am splitting a one BB loop into two BB. >>&...

I am splitting a one BB loop into two BB. Basically, the one loop BB has 3 incoming values, one form back edge two from other edges. I want to extract the PHIs from the other two edges out into it's own BB and delete that from the loop, then redirect the backedge to the loopbody (non extracted portion) and create a new PHI coming from the extracted BB and the backedge. I can do this;