Displaying 1 result from an estimated 1 matches for "iterationen".
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iteration
2008 Nov 20
5
summary statistics into table/data base, many factors to analyse
...0 2.000 3.000 3.833 5.500 8.000 2.714160
y 2 1.000 3.000 3.500 3.333 4.000 5.000 1.366260
z 1 1.0 3.5 6.0 5.0 7.0 8.0 3.6055513
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I tried to unlist the matrices, but it did not help much.
it <- NULL # "it" - Iterationen
for (i in 1:nlevels(z)){
it[[i]] <- unlist(s1[[i]])}
Help to any of the three points is greatly appreciated.
Cheers,
Gerit
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