search for: item7

...this has been answered somewhere else, but I have been searching for an answer all day and not been able to find one. I am trying to plot a path diagram for a CFA I have run, I have installed Rgraphviz and run the following: pathDiagram(cfa, min.rank='item1, item2, item3, item4, item5, item6, item7, item8, item9, item10, item11, item12', max.rank='SMP, AAAS', file='documents') I get the following message and output: Running dot -Tpdf -o documents.pdf documents.dot digraph "cfa" { rankdir=LR; size="8,8"; node [fontname="Helvetica" fo...

Hello all Is there a way reducing the number of characters in a list so that just the left n numbers of characters is given? For example, If I have a list, listnames, which consists of 4 strings of 6 characters; >listnames [1] "item12" "item34" "item56" "item78" Is there a way to reduce this so only the 5 characters on the lefthand side are given (similar to the LEFT function in Excel) So that I'd get a list like this >listnames [1] "item1" "item3" "item5" "item7" Thanks Tony [[a...

...s as an example. *Subject* *Factor1* *Factor2* *Condition* *ReadingTime* *Item* 1 A A A 238 Item1 1 A A A 369 Item5 1 A A A 494 Item9 *.* *.* *.* *.* *.* *.* *.* *.* *. * *.* *.* *.* 1 B A C 294 Item22 1 B A C 694 Item26 *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* 8 A A A 334 Item3 8 A A A 366 Item7 *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* *.* I did ANOVA by using the following : result.subject=aov(ReadingTime~Factor1*Factor2 + Error(Subject/(Factor1*Factor2)), data=data), AND result.item=aov(ReadingTime~Factor1*Factor2 + Error(Item/(Factor1*Factor2)), data=data). Both both functions ret...

Suppose I have a data frame like "dat" below. For some context, this is the format that represents student's taking a computer adaptive test. first.item is the first item that student was administered and then score.1 is the student's response to that item and so forth. item.pool <- paste("item", 1:10, sep = "") set.seed(54321) dat <- data.frame(id =