Displaying 5 results from an estimated 5 matches for "item6".
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2013 Apr 16
1
Path Diagram
...ies if this has been answered somewhere else, but I have been
searching for an answer all day and not been able to find one.
I am trying to plot a path diagram for a CFA I have run, I have installed
Rgraphviz and run the following:
pathDiagram(cfa, min.rank='item1, item2, item3, item4, item5, item6,
item7, item8, item9, item10, item11, item12', max.rank='SMP, AAAS',
file='documents')
I get the following message and output:
Running dot -Tpdf -o documents.pdf documents.dot
digraph "cfa" {
rankdir=LR;
size="8,8";
node [fontname="Helvetica&q...
2006 Jul 20
2
Timing benefits of mapply() vs. for loop was: Wrap a loop inside a function
..., while
etc as a matter of practice.
However, it seems the mapply function in this case is slower (in terms
of CPU speed) than the for loop. Here is an example.
# data needed for example
items <- list(item1 = c(0,1,2), item2 = c(0,1), item3 = c(0,1,2,3,4),
item4 = c(0,1), item5=c(0,1,2,3,4),
item6=c(0,1,2,3))
score <- c(2,1,3,1,3,2)
theta <- c(-1,-.5,0,.5,1)
# My old function using the for loop
like.mat <- function(score, items, theta){
like.mat <- matrix(numeric(length(items) * length(theta)), ncol =
length(theta))
for(i in 1:length(items)) like.mat[i, ] <- pcm(th...
2012 May 29
1
model frame and formula mismatch with latent class analysis poLCA
...binary scores of, for instance, 200 students on 100 items. These numbers
could even be more in due course. The resulting dataframe on which i want to
perfrom LCA looks like shown below (first five person). Each row
corresponds to scores of a person on the 100 items.
item1 item2 item3 item4 item5 item6 . . . . . . item97 item98 item99
item100
1 1 0 1 1 1 . . . .
. . 1 0 1 1
0 0 0 0 1 1 . . . .
. . 1 0...
2007 Nov 25
1
Constructin a call of function including permutation of column names - how to escape parentheses?
Dear R-users,
I would like to construct a list of arguments for a function in a format
function (list(item1=c("A","B"), item2=c("B","C")), item3=...):
The individual vectors in the list are permutations of colnames of a
dataframe.
The trouble is that I am not able to handle escaping of parentheses
correctly.
I was trying the following:
library(gregmisc)
2010 Feb 25
2
Restructure some data
Suppose I have a data frame like "dat" below. For some context, this is the format that represents student's taking a computer adaptive test. first.item is the first item that student was administered and then score.1 is the student's response to that item and so forth.
item.pool <- paste("item", 1:10, sep = "")
set.seed(54321)
dat <- data.frame(id =