search for: isins

Dear R help I was hoping you might be able to show me how to write a loop function take would ccomplish this task. library(prob) { a <- sample ( 1:20, 100, replace=T) b<-sample(5:24,100,replace=T) } dd <- data.frame(a,b) dd # code piece I am looking for if(subset(dd,c(1,23,ordered=F))is found))( print subset) else( continue evaluating subsets) subset(dd,isin(dd,c(1,23), ordered =

Hi David, I tried the following and get the below error messages.... con = blpConnect(show.days="trading",na.action="previous.days",periodicity="da ily")# connecting Bloomberg > dat <- blpGetData(con,"US4009703799 Equity","PX_LAST",start=as.chron(as.Date("01/01/2005",

Hi R, Can I convert ISIN numbers into Bloomberg tickers in the RBloomberg package? BR, Shubha [[alternative HTML version deleted]]

...ned stock would've performed over the period in question. I am using quantmod in R to download the historical data from yahoo and then analyzing it using PerformanceAnalytics. My problem is that, as our screens are done using Bloomberg, my list of screened stocks only has Bloomberg tickers and ISINs. Does anybody know of a method which could convert ISINs to yahoo tickers/symbols?? Or a method of accessing yahoo historical data from an ISIN (instead of a symbol call)? I would prefer not to use RBloomberg to download the data as the data calls would be extensive in testing. Thank you!!

I''ve seen this happen before, not sure why. I changed ''phy:'' to ''file:'' and it worked. I later rebooted and ''phy:'' worked again. So you might try ''file:'' rather than ''phy:''. -- Ray -----Original Message----- From: xen-users-bounces@lists.xensource.com

I am trying to use if...else loop and have included a code snippet which I might like to expand. Maybe you could steer me in the right direction. library(stats) library(prob) { a <- sample ( 1:4,100, replace=T,prob=c(0.1,0.2,0.5,0.3)) b<-sample(3:6,100,replace=T,prob=c(0.2,0.2,0.2,0.4)) } dd <- data.frame(a,b) if (subset finds a vector) ( print that vector) (else

All: Are there any functions out there for selecting all the points in a region of a plot. I envision something like the identify() function except one could circle a cloud of points (and perhaps a vector would be returned of the same length as the points plotted indicating logical membership in the circled cloud). Perhaps someone has done something with the locator() function that would

Hello there! does any one know how to convert the following type of data > z DATE TIME ISIN PRICE VOL ID_DEAL RANK 1881 2009-09-11 10:30:59 RTS-9.09 117445 10 98200801 1 1882 2009-09-11 10:31:59 RTS-9.09 117450 1 98202144 6 1883 2009-09-11 10:32:59 RTS-9.09 117285 1 98203075 1 1884 2009-09-11 10:33:59 RTS-9.09 117180 3 98203828 1 1885 2009-09-11

Hi, Before I try to code this myself, I'd like to know if anyone has a fixed-point routine to compute the cos and acos functions. All I need is around 3-digit accuracy. Thanks. Jean-Marc -- Jean-Marc Valin, M.Sc.A., ing. jr. LABORIUS (http://www.gel.usherb.ca/laborius) Université de Sherbrooke, Québec, Canada -------------- next part -------------- A non-text attachment was

I'm doing these manipulations on the data frame and wondering why does R have to remember historical data on my operation and not just keep the needed info. Probably a basic fundamentals of the way R handles data .. Pls point me to the manual if possible .. I have this Index data: > head(NIFTY_INDX) Constituents.list.of.S.P.CNX.Nifty X X.1 X.2 X.3

Hi, I''m learning puppet as that is what they use at my current work, though that could change... Question 1: Last place of work, we wrote our own perl based system which was extremely simple and concise to drive - eg to distribute a file, we would put it in: <nfsdir>/noarch/dist/etc/syslog-ng/syslog-ng.conf/ # which means create a file /etc/syslog-ng/syslog-ng.conf on the

Hello everybody. I found out the other day something quite astonishing (which I guess is not astonishing at all to those in the know): in d-dimensional space, determining whether a given point is inside the convex hull of a set of n points is elegantly and quickly solvable using linear programming. If the columns of matrix "ff" are the coordinates of the set of points, then in d=2

Hello, I'm a R newcomer and I'm wondering the kind of data structure that would best fit to my problem: my data are equities (stocks) : so I have a time serie (say 1 year of weekly data), and a bunch of qualitative + quantitative variables : the sector of the stock (biotech/finance...), the geographical region, the name, ISIN code, P/E ratios, whatever... The data.frame is perfect for the

Dear R, I have a covariates matrix with 10 observations, e.g. > X <- matrix(rnorm(50), 10, 5) > X [,1] [,2] [,3] [,4] [,5] [1,] 0.24857135 0.30880745 -1.44118657 1.10229027 1.0526010 [2,] 1.24316806 0.36275370 -0.40096866 -0.24387888 -1.5324384 [3,] -0.33504014 0.42996246 0.03902479 -0.84778875 -2.4754644 [4,] 0.06710229 1.01950917

Hi all, I'd like to know, if I can solve this with a shorter command: a <- rnorm(100) which(a > -0.5 & a < 0.5) # would give me all indices of numbers greater than -0.5 and smaller than +0.5 I have something similar with a dataframe and it produces sometimes quite long commands... I'd like to have something like: which(within.interval(a, -0.5, 0.5)) Is there anything I

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