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How can I print the definition of a function that is in the base package? for example, if I type: which.min I get function (x) .Internal(which.min(x)) <environment: namespace:base> How can I see the definition of this function? Thanks.

I'm sure there is a more general way to ask this question but how do you use the elements of a character vector as names of objects in an expression? For example, say you have: a = c(1,3,5,7) b = c(2,4,6,8) n=c("a","b") and you want to use the names a and b in a function (e.g. sum) sum(eval(as.name(n[1])),eval(as.name(n[2]))) works but what is a simpler way to

I have a matrix which has colnames and I would like to send this matrix using sendmailR. How can I convert this simple matrix to a format which can be used as the body variable in sendmailR? I see how I can create a file attachment using mime_part but I would like to send the matrix in the body of the email. The matrix looks like: ABD DEF GHI JKL MNO TOT [1,] 0.44 0.81 1.67 0.37

I am using the getQuote function in the Quantmod package to retrieve the % change for a stock as follows: > getQuote("aapl",what=yahooQF(c("Change Percent (Real-time)"))) Trade Time %Change (RT) aapl 2012-10-11 03:41:00 N/A - -1.67% How can I extract the numeric "change %" which is being returned as a factor so that I can use it in other

I would like to have a function which gets data, does a calculation and prints a result and then waits some number of seconds and repeats. If I use Sys.sleep, the execution is pausing but the function output is buffered so that it all comes out when the function terminates. How can I get output while the function continues to execute?

Can someone please tell me why the following (last line) doesn't work (as I expect it to :-) library(quantmod) a = getSymbols("MSFT",from="2009-3-01") a MSFT eval(as.name(a)) MSFT$MSFT.Adjusted b=paste(a,'$MSFT.Adjusted',sep='') b eval(as.name(b)) Why does this last line not work the way the earlier eval does? Thanks.

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to