Displaying 3 results from an estimated 3 matches for "iotw".
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2007 Jul 15
2
Break during the recursion?
Hi,
Is it possible to break using if-condition during the recursive function?
Here is a function which almost works. It is for inorder-tree-walk.
iotw<-function(v,i,Stack,Indexes) # input: a vector and the first index (1), Stack=c(), Indexes=c().
{
print(Indexes)
# if (sum(i)==0) break # Doesn't work...
if (is.na(v[i])==FALSE & is.null(unlist(v[i]))==FALSE)
{Stack=c(i,Stack); i=2*i; iotw(v,i,Stack,Indexes)}
Indexes=c(Indexes,St...
2004 Aug 06
0
project 'Sphinx' kicked off
...feedback nature of the IIR.
There are a bunch of IIR filters used in speex. It seems to me that using
the rounded impulse responses of those filters (up to limit of precision)
would be a good approach, as opposed to redesigning all the filters. I've
done a few tests, and it looks promising.
IOTW, use matlab or octave to get the high precision impulse reponse of
the IIR, scale it according to fixed point reqs., then round it. Assuming
that the original IIR filter is stable, the impulse response will
eventually subside so that the coefficients round to less than the fixed
point precision, i...
2004 Aug 06
5
project "Sphinx" kicked off
<with Prof. Farnsworth voice> "Good News, everyone".
I've just kicked off project "Sphinx". Which is supposed to
sound like "Speex" merged with "INT". ;) Meaning I am working
on an integer encoder and decoder.
It looks like I will be pulling in a new "integer plumbing"
into the foundation of the codec, comparing the results with
the old