search for: inverv

...(x) elements belong to. So, clearly, the first element of x, 0, belongs to (-0.008,0.994] because -0.008 < 0 <= 0.994. However, when I come to the 14th element of x, that is, 2, I don't see that it belongs to (2,3], because 2 < 2 <= 3, is strictly false according to the standard inverval notation (http://en.wikipedia.org/wiki/Interval_notation). Maybe, there is something I have not understood of either the cut function or the interval notation. Do you have any comments? Thanks, Sergio.

...you get something that looks right, let me know and I'll apply it :) > On a related note, I'm a bit surprised that 2-nd order partition consists of > basic blocks. I'd more expect that it consisted of Interval's. As it stands, > it's not easy to tell which 1-st order invervals are contained in a given > 2-nd order interval. That does seem strange. If you would like to change/refactor this code, feel free. -Chris -- http://nondot.org/sabre/ http://llvm.cs.uiuc.edu/

...' is after the change. I must admit the change does not look 100% right to me yet. On a related note, I'm a bit surprised that 2-nd order partition consists of basic blocks. I'd more expect that it consisted of Interval's. As it stands, it's not easy to tell which 1-st order invervals are contained in a given 2-nd order interval. - Volodya -------------- next part -------------- A non-text attachment was scrubbed... Name: IntervalPartition.diff Type: text/x-diff Size: 1456 bytes Desc: not available URL: <http://lists.llvm.org/pipermail/llvm-dev/attachments/20050429/396...

...looks right, let me know and I'll apply > it :) > > > On a related note, I'm a bit surprised that 2-nd order partition consists > > of basic blocks. I'd more expect that it consisted of Interval's. As it > > stands, it's not easy to tell which 1-st order invervals are contained in > > a given 2-nd order interval. > > That does seem strange. If you would like to change/refactor this code, > feel free. Okay. I've done first round of refactoring and currently writing some code of mine that uses IntervalPartition which should uncover any...