search for: inverted

I'm having the most curious error while using the sem package. For the model I'm working with, I keep getting the following error: Error in J[cbind(1:n, observed)] <- 1 : subscript out of bounds I''ve used debug=TRUE with sem, and there don't appear to be any problems with model - there are no latent variables in this model. The variables in the covariance matrix

...that in the predicated instruction do not contain only the predicate register, but a predicate register and boolean value pair, the boolean value stating if the instruction is to be executed only if the register is true(normal behavior of predicate regs) or only if the predicate reg is false("inverted behaviour") So, for eample if we have a machine without "not equal"(ne) operation and we have a code where we would have an "ne" comparison followed by predicated jump, it is possible to do this with "eq" comparison followed by a inverted-predicate predicated ju...

Dear List, I am using the wireframe function in the lattice package, and I am wondering if it is possible to invert the default axes orientation for x and y axes... what parameter should I look for? Best regards, Simone Gabbriellini

Can R invert a 160000x160000 matrix with all positive numbers? Thanks a lot!

Hi uRsers, when inverting a 2 by 2 matrix using solve, I encountered a error message: solve.default(sigma, tol = 1e-07) : system is computationally singular: reciprocal condition number = 1.7671e-017 and then I test the determinant of this matrix: 6.341393e-06. In my program, I have a condition block that whether a matrix is invertible like this: if(det(sigma)<1e-7) return NULL;

Hello, just a simple question How can I do to invert the sign of a number? (for example: -4 to 4, 2 to -2 and so on..) I was looking for a specific function in R but I didn't found it... thank you Francesco -- View this message in context: http://www.nabble.com/Invert-the-sign-of-a-number-tp26110267p26110267.html Sent from the R help mailing list archive at Nabble.com.

Hi; I am having problems inverting matrices using the function solve() For example R can not invert the following matrix [,1] [,2] [,3] [,4] [,5] [1,] 25 500 11250 275000 7.106250e+06 [2,] 500 11250 275000 7106250 1.906250e+08

...(1:25,ncol=5) # define b to get an orthogonal matrix b<-b+t(b) bb<-eigen(b,symmetric=T) aah<-bb$vectors%*%diag(1/sqrt(diag(a))) aa<-aah%*%t(aah) # aa should have the same eigenvalues as a and should be #invertable,however, solve(aa) # can not be solved solve(aa,tol=1e-19) # can be inverted, however, it is not symmetric and furthermore, solve(aa,tol=1e-19)%*%aa # deviate much from the identity matrix I have already define aa to make sure it is symmetric. So the inverse should be symmetric. Does the problem come from the rounding error since the eigenvalue is smaller than the machin...

Hello, I am trying to generate random survival times by inverting the function,  S(t)= exp(b*F(t)), where b is constant and F(t) is some cumulative distribution function, let say that F(t) is cdf of normal distribution or any others distributions.   as we know that S(t) has uniform distribution on  (0,1) so we can write that U= exp(b*F(t)), where U is uniform (0,1). Now to generat the time t, we

Hello R-Users, I have to invert a matrix 3000X3000 and the solve method doesn't work or it is too slow. Are there any methods to invert a big matrix? Regards Stefan --------------------------------- [[alternative HTML version deleted]]

Hi.. I have to invert a 15000 x 15000 matrix (generalized inverse). I do run the process on a fairly powerful computer. but still complains indufficient memory. Is there a way one can invert a large matrix in some other efficient manner. Thanks Harsh --------------------------------- [[alternative HTML version deleted]]

Is there an easy way to invert a table? (not to solve for the inverted matrix, just swap rows for columns & vice versa). I've gone through my data manipulation bible (Phil Spector's book), but to no avail. [[alternative HTML version deleted]]

Hi all. As the subject has come up. Powerware ups may contain several cpu's and different firmware versions. Five of them is always ordered in a specific way. 1 control panel 2 inverter 3 rectifier 4 net interface card 5 display control So if a ups have a inverter cpu but not a control panel it sets the firmware revision to 00.00 to the control panel cpu, and get the version for the

Hello everyone I was wondering how would one simulate from a Normal Wishart Distribution in R. A normal inverted Wishart distribution is denoted by NIW (M,C,d,S), where X/(Sigma) ~ N( M,C,(Sigma) ) -> a matrix normal distribution, (Sigma) -> column dispersion matrix (Sigma) ~ IW (d,S) -> inverted Wishart distribution Thanks a lot ! Best Shantanu [[alternative HTML version deleted]]

Full_Name: Ravi Varadhan Version: 2.8.1 OS: Windows Submission from: (NULL) (162.129.251.19) Inverting a matrix with solve(), but using LAPACK=TRUE, gives erroneous results: Here is an example: hilbert <- function(n) { i <- 1:n; 1 / outer(i - 1, i, "+") } h5 <- hilbert(5) hinv1 <- solve(qr(h5)) hinv2 <- solve(qr(h5, LAPACK=TRUE)) all.equal(hinv1, hinv2) #

I've looked around but I can't find the method in R for testing whether the resulting estimated coefficients of an AR model imply that the model is invertible. To quote from eric zivot's blue book : " the AR(p) is invertible provided the rots of the characteristic equation Phi(z) = 1 - phi_1*z - phi_2*z^2 = phi_3*z^3 - ..... Phi_p*z^p = 0 lie outside the complex circle".

...01:00.0 0300: 10de:0dfc (rev a1) 01:00.0 VGA compatible controller: NVIDIA Corporation GF108GLM [NVS 5200M] (rev a1) xrandr available resolutions reported (from Linux 5.7 using Xorg): Screen 0: minimum 320 x 200, current 5120 x 1440, maximum 16384 x 16384 LVDS-1 unknown connection (normal left inverted right x axis y axis) 1600x900 59.99 + 40.00 5120x1440 60.00 1360x1020 73.97 1152x864 59.97 1024x768 59.95 800x600 59.96 640x480 59.94 DP-1 disconnected (normal left inverted right x axis y axis) DP-2 connected primary 5120x1440+0+0 (no...

When I execute xrandr I receive, omitting the details of resolution options, Screen 0: minimum 320 x 200, current 1920 x 1080, maximum 8192 x 8192 LVDS-1 unknown connection (normal left inverted right x axis y axis) DP-1 disconnected (normal left inverted right x axis y axis) HDMI-1 disconnected (normal left inverted right x axis y axis) HDMI-2 connected 1920x1080+0+0 (normal left inverted right x axis y axis) 698mm x 392mm I am running on a Alienware 18 laptop that as far as I know has...

Dear Rers, I have threes series, x, y, z and I want to fit a model z ~ x + y. First of all, I fit a lm. I found the residuals are correlated, by looking at the acf() and pacf(). Then I tried to fit a gls model allowing residuals to be correlated (correlation = corARMA(p=5, q=1)): y.na <- as.data.frame(y[complete.cases(y),]) y.gls <- gls(z ~ x + y, data = y.na, correlation=corARMA(p=5,

Hi! This is probably a very trivial question. Is there an easy way to invert the y-axis (low values on top) when using the function barplot()? Thanks, Jörg [[alternative HTML version deleted]]