search for: inutitive

Hi Hadley, Thanks for the counterpoint. Response below. On Thu, May 16, 2019 at 1:59 PM Hadley Wickham <h.wickham at gmail.com> wrote: > The existing behaviour seems inutitive to me. I would consider these > invariants for n vector x_i's each with size m: > > * nrow(rbind(x_1, x_2, ..., x_n)) equals n > Personally, no I wouldn't. I would consider m==0 a degenerate case, where there is no data, but I personally find matrices (or data.frames) with rows...

...t; on Thu, 16 May 2019 15:47:57 -0700 writes: > > > Hi Hadley, > > Thanks for the counterpoint. Response below. > > > On Thu, May 16, 2019 at 1:59 PM Hadley Wickham <h.wickham at gmail.com> > wrote: > > >> The existing behaviour seems inutitive to me. I would consider these > >> invariants for n vector x_i's each with size m: > >> > >> * nrow(rbind(x_1, x_2, ..., x_n)) equals n > >> > > > Personally, no I wouldn't. I would consider m==0 a degenerate case, > where...

Hi all, Apologies if this has been asked before (a quick google didn't find it for me),and I know this is a case of behaving as documented but its so unintuitive (to me at least) that I figured I'd bring it up here anyway. I figure its probably going to not be changed, but I'm happy to submit a patch if this is something R-core feels can/should change. So I recently got bitten by

...t; Gabriel Becker >>>>> on Thu, 16 May 2019 15:47:57 -0700 writes: > Hi Hadley, > Thanks for the counterpoint. Response below. > On Thu, May 16, 2019 at 1:59 PM Hadley Wickham <h.wickham at gmail.com> wrote: >> The existing behaviour seems inutitive to me. I would consider these >> invariants for n vector x_i's each with size m: >> >> * nrow(rbind(x_1, x_2, ..., x_n)) equals n >> > Personally, no I wouldn't. I would consider m==0 a degenerate case, where > there is no data, but I...

The existing behaviour seems inutitive to me. I would consider these invariants for n vector x_i's each with size m: * nrow(rbind(x_1, x_2, ..., x_n)) equals n * ncol(rbind(x_1, x_2, ..., x_n)) equals m Additionally, wouldn't you expect rbind(x_1[i], x_2[i]) to equal rbind(x_1, x_2)[, i, drop = FALSE] ? Hadley On Thu, May 16...