search for: interpr

Bonjour, je voulais savoir si wxruby2 est intégré à l''interpréteur ruby? Que veut dire $0 ? merci Sebastien _______________________________________________ wxruby-users mailing list wxruby-users@rubyforge.org http://rubyforge.org/mailman/listinfo/wxruby-users

Hello, [really hoping not to ask something the 1001th time] I need single backslashes printed for generating TeX-code. That works: > print("\begin{tabular}") [1] "\begin{tabular}" But \h seems to be interprated in some way: > print('\hline') [1] "hline" Hm, trying to mask the backslash: > print('\\hline') [1] "\\hline" But I need "\hline"... Is there a way without generating strange code in a temporary file for "sed"ing it? I...

Hi, I am wondering how I should interpreate the output of optFederov() in AlgDesign. Specially I want to know what is $D, $A, $Ge and $Dea, which one I can use as an efficiency to say how good the optimal design is. I only know when a orthogonal design comes, $D = 1. I red the pdf document -- vignette("AlgDesign") [Jus...

...here because if the regressions are done separately on each cloud, then there really isn't a relationship between x and y. I was just wondering 1) what assumption in regression is being violated in the first case or 2) possibly if the regression is valid and the results just have some different interpreation ? Thanks. Mark -------------------------------------------------------- This is not an offer (or solicitation of an offer) to buy/se...{{dropped}}

...dans " }" > for(k in 1:(na-1)){ + if(pos==1) {donGeno[[k]] <- donGeno[[k]][2:C[k]]} + if(pos==C[k]){donGeno[[k]] <- donGeno[[k]][1:(C[k]-1)]} + else{donGeno[[k]] <- c(donGeno[[k]][1:(pos-1)],donGeno[[k]][(pos+1):C(k)])} + } Erreur dans C(k) : objet non interprétable comme un facteur > } Erreur : erreur de syntaxe dans " }" Have you got some ideas? ___________________________________________________________________________ [[alternative HTML version deleted]]

...e number of recursive calls to 100? What is its relation to the "expressions" setting in options()? More fundamentally, I would appreciate any comment on this implementation or suggestion about the best way of implementing streams in R. My objective is to implement logic programming interpreter in R as done in LISP by G.F.Luger in his book or by Abelson & Sussman in "Structure and Interpreation of Computer Program". Thank you, Gabriel ### ### Examples ### > fib<-fibonacci.stream(0,1) Note that the fibonacci.stream() function is a nonterminating recursive...

...f factors. But why testing data;frames? If you go that way using random structures, you can also try : >> >>> median(list(1,2),list(3,4),list(4,5)) >> Error in if (na.rm) x <- x[!is.na(x)] else if (any(is.na(x))) return(x[FALSE][NA]) : >> l'argument n'est pas interpr?table comme une valeur logique >> De plus : Warning message: >> In if (na.rm) x <- x[!is.na(x)] else if (any(is.na(x))) return(x[FALSE][NA]) : >> la condition a une longueur > 1 et seul le premier ?l?ment est utilis? >> >> giving a message which, despite of his...

...here because if the regressions are done separately on each cloud, then there really isn't a relationship between x and y. I was just wondering 1) what assumption in regression is being violated in the first case or 2) possibly if the regression is valid and the results just have some different interpreation ? Thanks. Mark -------------------------------------------------------- This is not an offer (or solicitation of an offer) to buy/se...{{dropped}} ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do...

...ht side which are of equal heights in user coordinates. I don't understand the meaning of: "which are of equal heights in user coordinates" I'm working with monthly time series, with a clear seasonal cycle, but a not so clear trend, is just what I'm looking for. How do I interprate the height of such bars? Thanks Antonio

...nted what happens for this case, > (but read on ...) and it is *not* true that the documentation does not say, since 2013, it has contained exclude: levels to remove for all factors in ?...?. If set to ?NULL?, it implies ?useNA = "always"?. See ?Details? for its interpretation for non-factor arguments. > > For the example, in R 3.3.1, the result like in R 2.7.2 can be obtained with useNA = "ifany" and 'exclude' unspecified. > > Yes. What should we do? > I currently think that we'd want to change the line > > use...

...use lschape="logoff" and eschape=list(offset=-2) regWeib0<-vglm(eqn0,family=weibull(lshape='logoff',eshape=list(offset=-2)),subset(br, fdh<1)) Erreur dans if ((temp <- sum(wz[, 1:M, drop = FALSE] < wzepsilon))) warning(paste(temp,? : ? l'argument n'est pas interpr?table comme une valeur logique De plus : Message d'avis : In log(theta + offset) : production de NaN Finaly i use the above function to find initial value for shape (a) and scale (b)? weibullPar<-function(x){ ?f<-function(p,mu=mean(x), sig=((length(x)-1)*var(x))/length(x)){ ????? n<...

Hello, Is there a reason for the following behaviour? > mean(c("1","2","3")) [1] NA Warning message: In mean.default(c("1", "2", "3")) : l'argument n'est ni num?rique, ni logique : renvoi de NA But: > var(c("1","2","3")) [1] 1 And also: >

...ngst what the list in the law permits and that are thus void. The GPL is all that gives you permission to distribute. If it is void then you have no permission at all to distribute any covered code. > Both legal systems have the same results: They prevent the GPL from using it's > own interpretation os what a derivative work is and the rules from the laws > apply instead. So apply copyright law without a license. You can't distribute. I agree that the FSF interpretation about distributing source with the intention that the end user does the link with other components is prett...

...e in the case of factors. But why testing data;frames? If you go that way using random structures, you can also try : > >> median(list(1,2),list(3,4),list(4,5)) > Error in if (na.rm) x <- x[!is.na(x)] else if (any(is.na(x))) return(x[FALSE][NA]) : > l'argument n'est pas interpr?table comme une valeur logique > De plus : Warning message: > In if (na.rm) x <- x[!is.na(x)] else if (any(is.na(x))) return(x[FALSE][NA]) : > la condition a une longueur > 1 et seul le premier ?l?ment est utilis? > > giving a message which, despite of his length, doesn't...

...ng from judgements, you would know that judges just look at the parts of the GPL that are not in conflict with the law. Judges know that making the GPL void as a whole would be a desaster. > > Both legal systems have the same results: They prevent the GPL from using it's > > own interpretation os what a derivative work is and the rules from the laws > > apply instead. > > So apply copyright law without a license. You can't distribute. I > agree that the FSF interpretation about distributing source with the > intention that the end user does the link with o...

...checks to this message upon receipt. ------------------------------------------------------------------------------------ L'information communiqu?e dans les courriels en provenance de la Banque du Canada est soumise de bonne foi, mais elle ne saurait lier la Banque et ne doit aucunement ?tre interpr?t?e comme constituant une obligation de sa part. Le pr?sent courriel peut contenir de l'information privil?gi?e ou confidentielle. La Banque du Canada ne renonce pas aux droits qui s'y rapportent. Toute diffusion, utilisation ou copie de ce courriel ou des renseignements qu'il contient...

...is nothing in conflict with law about prohibiting distribution. And you cant' just unilaterally pick parts of the licence that permits distribution that you like and ignore the rest. >> So apply copyright law without a license. You can't distribute. I >> agree that the FSF interpretation about distributing source with the >> intention that the end user does the link with other components is >> pretty far off the wall, but static binaries are clearly one 'work as >> a whole' and dynamic linkage is kind of fuzzy. US juries are >> supposed to...

...; > and it is *not* true that the documentation does not say, since > 2013, it has contained > > exclude: levels to remove for all factors in ?...?. If set to ?NULL?, > it implies ?useNA = "always"?. See ?Details? for its > interpretation for non-factor arguments. > > > > > For the example, in R 3.3.1, the result like in R 2.7.2 can be obtained with useNA = "ifany" and 'exclude' unspecified. > > > > Yes. What should we do? > > I currently think tha...

...ponents, so that the compiled binaries are not derived from LLVM. Is that true? The runtime library components state that they are licensed under http://www.opensource.org/licenses/mit-license.php which does not contain a specific clause regarding binary redistribution. This seems to have been interpreted as not placing any restrictions on binary redistribution, i.e. that "all copies" has somehow been interpreted as "copies in source code form". (Different licenses such as Boost, zlib, and bzip2 etc. do not require copyright notices for binary redistributions.) Is it suff...

...>> and it is *not* true that the documentation does not say, >> since 2013, it has contained >> >> exclude: levels to remove for all factors in ?...?. If >> set to ?NULL?, it implies ?useNA = "always"?. See >> ?Details? for its interpretation for non-factor >> arguments. >> >> >> > > For the example, in R 3.3.1, the result like in R >> 2.7.2 can be obtained with useNA = "ifany" and 'exclude' >> unspecified. >> > >> > Y...