search for: intergenerational

...an object of class "varest" generated by VAR() -exactly the class of object that var.2c is: > class(var.2c) [1] "varest" May it be that I'm using the latest version of R -in Windows- (ie 2.15.3 ), perhaps? Jose Wrap Up and Run 10k is back! Also, new for 2013 ? 2km intergenerational walks at selected venues. So recruit a buddy, dust off the trainers and beat the winter blues by signing up now: http://www.ageuk.org.uk/10k Milton Keynes | Oxford | Sheffield | Crystal Palace | Exeter | Harewood House, Leeds | Tatton Park, Ches...

...> Twitter @jose.iparraguirre@ageuk Tavis House, 1- 6 Tavistock Square London, WC1H 9NB www.ageuk.org.uk<http://www.ageuk.org.uk> | ageukblog.org.uk<http://ageukblog.org.uk/> | @ageuk<http://twitter.com/ageukpa>campaigns Wrap Up and Run 10k is back! Also, new for 2013 – 2km intergenerational walks at selected venues. So recruit a buddy, dust off the trainers and beat the winter blues by signing up now: http://www.ageuk.org.uk/10k Milton Keynes | Oxford | Sheffield | Crystal Palace | Exeter | Harewood House, Leeds | Tatton Park, Ches...

In R I have 3 variables x,y and z that contain: | x y z [1,] 1 12 122 [2,] 1 13 113 [3,] 1 11 111 [4,] 3 13 123 [5,] 4 14 134 [6,] 5 15 155| I am creating a coplot with the following syntax: |given.depth<- co.intervals(z, number=3, overlap=.1) coplot(x~y|z,pch=19,col="red",cex=1.5,given.values=given.depth)| The resulting plot however has has bars in the

Dear useRs, In a thesis, I found a mention of the use of pairwise deletion in linear regression and GLM (binomial family). The author said that he has used R to do the statistics, but I did not find the option allowing pairwise deletion in both lm and glm functions. Is there somewhere a package allowing that ? Thanks, Arnaud [[alternative HTML version deleted]]

Dear useRs, With the following set of command i managed to create the copula density ================================================ >library(MASS) >library(evd) >X<-matrix(sample(1:3000), ncol=2) >U=cbind(rank(X[,1])/(nrow(X)+1),rank(X[,2])/(nrow(X)+1)) > mat1=kde2d(U[,1],U[,2],n=150) image(mat1$x,mat1$y,mat1$z,col= rev(heat.colors(1500)),xlab="",ylab="")

I have a data. frame to which you want to change the names to some of their columns. For example: > seba <- data.frame ('constant' = 3, 'numbers' = 1: 10, 'letters' = LETTERS [1:10], otros = 2:11) List their names: > names (Seba) [1] "constant" "numbers" "letters" I want to rename c the column called constant and b the column

Hello, I have a problem regarding calculation of Cumulative Incidence Function. The event of interest is failure of bone-marrow transplantation, which may occur due to relapse or death in remission. The data set that I have consists of- lifetime variable, two indicator variables-one for relapse and one for death in remission, and the other variables are donor type (having 3 categories), disease

Hi, I am trying to draw a dotted circle by using symbols command: symbols(0, 0, circles = 1, inches = FALSE, fg = 'gray', lty=2) But it gives me a solid line. I was just wondering whether am I making a mistake? Ved [[alternative HTML version deleted]]

Hi all, I want to plot a facet plot with column names as x and column values as y. One plot for each row. here is part of my dataset: Gene T0h T0.25h T0.5h T1h T2h T3h T6h T12h T24h T48h NM_001001130 68 95 56 43 66 62 68 90 63 89 NM_001001144 0 1 4 0 1 1 1 4 1 2 NM_001001152 79 129 52 50 24 45 130 154 112 147 NM_001001160 1 1 2 0 0 1 0 0 0 1 NM_001001176 0 0 0 0 0 0 0 0 0 0 NM_001001177

Dear all, I have a matrix with two columns: "Names" and "Values" In names: there are 4 groups they are, CK113234, CK116296, CK116292 and CK114042 I want to *sort values* (decreasing order) based on each group and take average of the *top two numbers* in each of the groups. > dput(x) structure(list(Names = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 5L, 5L, 5L, 5L, 2L,

Dear R Helpers, I'm struggling with a data preparation problem. I feel that it is a quite easy task but I don't get it done. I hope you can help me with that. I have a data frame looking like this: ID <- c(1,1,1,2,2,3,3,3,3) T <- c(1,2,3,1,4,3,5,6,8) x <- rep(1,9) df <- data.frame(ID,T,x) >df ID T x 1 1 1 1 2 1 1 3 1 2 1 1 2 4 1 3 3 1 3 5 1 3 6 1 3 8 1 I want to

Hello, How can I judge if a string is in a group of string? For example, I would like to have if (subpool in pool){ }else{ } Where > pool = c("s1","s2") > subpool = c("s1") How can I write the "subpool in pool" right in R? Thanks very much! Cheers, Rebecca ---------------------------------------------------------------------- This message,

Hi R bayesians, I need an advise how to resolve the two different estimates applying a traditional glm (TG) and a bayes glm (BG), and different results depending on the data formats of response data and the prior specs using bayesglm in R. I'm not familiar with bayes estimate and my colleague asked me to look into this because the EPA from France reported a quite different estimates for

Hi all, Thanks in advance for any help. I have a vector "b": b=c(1,1,1,2,3,4,3,2,1,1,1,1,1,2,3,4,5,4,3.5,3,2,1,1,1) Imagine b is river flow throughout time. I would like some code that will generate the following information: number of individual 'periods' where b>1 (= 2 in this case) period 1 length = 5, max = 4 period 2 length = 8, max = 5 I can't figure anything

Dear R experts, I have two matrix (seq & mat) & I want to retrieve in a new matrix all the numbers from mat that =1 (corresponding to the same row/ column position) in seq, or all the numbers in mat that =-1 in seq. - Replace all the numbers with NA if it's not 1/-1 in seq. There are some "NA"s in seq. seq=matrix(c(1,-1,0,1,1,-1,0,0,-1,1,1,NA),3,4)

Dear list members, I would like to create two series of plotted mean values and error bars, yet with different locations along the x-axis. Plotting of first series using plotCI with the standard arguments goes without any problem. However I do not succeed to add the second series in the same plot, which should be horizontally shifted from the first series along the x-axis. The “add=TRUE”

Hi all, newbie question: I am trying to set up a very simple loop without succeeding. Let's say I have monthly observation of two variables for a year - Sales_2012_01, Sales_2012_02, Sales_2012_03, .... (total sales for jan 2012,feb 2012, etc.) - Customers_2012_01, Customers_2012_02, .... (total number of customers for jan 2012, etc.) and I want to create new monthly variables in

Dear list, I'm working with a large data set, where I grouped several species in one group (guild). Then I reshaped my data as shown below. Now, I just want to have "Rep" only as 1 or 0. I'm not being able to change the values of rep>=1 to 1... tried many things and I'm not being successful! > melting=melt(occ.data,id.var=c("guild", "Site",

I have a large data frame ("data1") that looks like: A1 A2 A3 A4 A5 A6 A7 A8 A9 A10 A11 A12 A13 A14 A15 A16 A17 A18 A19 A20 [1,] 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 [2,] 0 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 0 0 0 0 [3,] 1 1 0 1 1 1 1 1 1 1 1 0 1 1 0 0 0 0 0 0 [4,] 1 1 1 1