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input_df
2009 Sep 28
4
How to assess object names within a function in lapply or l_ply?
Dear All,
to produce output of several columns of a data frame, I tried to use
lapply and also l_ply. In both cases, I would like to print a header
line containing also the name of the respective column in the data frame.
For example, I would like the following
lapply(data.frame(a=1:3, b=2:4), function(x) print(deparse(substitute(x))))
to produce:
[1] "a"
[1] "b"
and