Displaying 4 results from an estimated 4 matches for "infron".
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2010 Feb 14
4
[LLVMdev] A very basic doubt about LLVM Alias Analysis
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Alias Analysis Evaluator Mod/Ref Summary: 100%/0%/0%/0%
And here nowhere it shows even a may alias relation between i & j.
I am interpreting this by looking at No Alias/May Alias/Must Alias
outputs shown infron of them. eg
NoAlias: i32** %i, i32** %j
I interpret it as no alias relation between i & j.
Duncan Sands wrote:
> Hi Ambika,
>
>> Oh m sorry for that mistake as I had points to in mind.
>> But still what about the following prog:
>>
>> int main()
>> {...
2010 Feb 15
0
[LLVMdev] A very basic doubt about LLVM Alias Analysis
>
>
>
> And here nowhere it shows even a may alias relation between i & j.
> I am interpreting this by looking at No Alias/May Alias/Must Alias
> outputs shown infron of them. eg
>
> NoAlias: i32** %i, i32** %j
>
> I interpret it as no alias relation between i & j.
Because the pointers being used aren't named i & j anymore.
MayAlias: i32* %2, i32* %4
MayAlias: i32* %2, i32* %k
MayAlias: i32* %4, i32* %k
%2 = load i32**...
2010 Feb 14
0
[LLVMdev] A very basic doubt about LLVM Alias Analysis
Hi Ambika,
> Oh m sorry for that mistake as I had points to in mind.
> But still what about the following prog:
>
> int main()
> {
> int *i,*j,k;
> i=&k;
> j=&k;
> k=4;
> printf("%d,%d,%d",*i,*j,k);
> return 0;
> }
>
>
> here too i dont get <i,j> alias each other.
how are you
2010 Feb 14
4
[LLVMdev] A very basic doubt about LLVM Alias Analysis
Oh m sorry for that mistake as I had points to in mind.
But still what about the following prog:
int main()
{
int *i,*j,k;
i=&k;
j=&k;
k=4;
printf("%d,%d,%d",*i,*j,k);
return 0;
}
here too i dont get <i,j> alias each other.
Duncan Sands wrote:
> Hi ambika,
>
>> main() {
>> int i,*k;
>> k =