search for: infant

Displaying 20 results from an estimated 62 matches for "infant".

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2003 Mar 06
2
anova subhypotheses
Hello all, A really noddy question for you all: I''m trying without success to do some subhypothesis testing. Using simple anova model, with a toy dataset from a book. I have four factors A,B,C,D, and wish to test mu_C = mu_D. This is what I have tried: > contrasts(infants$group,how.many=1) <- c(0,0,1,-1) > contrasts(infants$group) [,1] A 0 B 0 C 1 D -1 > fit <- aov(age~group,data=infants) > summary(fit) Df Sum Sq Mean Sq F value Pr(>F) group 1 0.740 0.740 0.2693 0.6092 Residuals 21 57.727 2.749...
2010 Sep 07
1
how to combine several subsets?
I simply put, > NEVER=subset(infants$bwt,ISNO1) > UNTILPREGNANT=subset(infants$bwt, ISNO2) > ONCENOTNOW=subset(infants$bwt, ISNO3) and I wanna combine those three. I do it like ISNO=NEVER&UNTILPREGNANT&ONCENOTNOW and R tells me 1: In NEVER & UNTILPREGNANT : longer object length is not a multiple of shorter ob...
2008 Mar 28
2
Wrong story step running
...isation "$organisation_name"'' do |name, secondary_email, user_type, user_state, organisation_name| # ... end When I run a story containing these step calls: And a user called "Mr Kameron Friesen" of type END_USER and status APPROVED in organisation "My Infant School" And a user called "Mr Adam Kameron" of type END_USER and status APPROVED in organisation "My Infant School" And a user called "Mr Matching Username" with username " kameron_is_cool at technophobia.com" of type END_USER and status APPROVED...
2010 Nov 02
5
Question about ggplot2
Dear All, I am trying to graph a simple scatter plot where the x axis is year and the y axis is a percentage (percentage of infant death). Instead of plotting the raw data, I want to plot summary statistics such as mean and median. Here is the problem: the value range of y is between 0 and 1, but since infant death is a rare event, the mean and median is very low (something like 5%), which shows up as a horizontal line at the...
2010 Feb 05
0
Censored outcomes - repeated measures and mediators
Hello, In a study exploring transgenerational transmission of anxiety disorder we investigate whether infants react to experimentally induced mood changes of their mothers. We measured the time that an infant needed to cross a cliff (=crossing time) depending on whether his mother had previously undergone a mood induction (treatment) or not (control). The treatment is thus a within-subjects factor...
2013 May 29
0
"Unable to optimize" error returned in factanal using R-3.0.1, Windows 64 bit, and OpenBLAS
...e work shows that the failure is in the call to `optim`. Specifically, when the call __passes__, it returns: > nfit Call: NULL Uniquenesses: Fertility Agriculture Examination Education 0.420 0.492 0.270 0.005 Catholic Infant.Mortality 0.061 0.960 Loadings: Factor1 Factor2 Fertility -0.674 0.356 Agriculture -0.648 0.297 Examination 0.713 -0.471 Education 0.997 Catholic -0.178 0.953 Infant.Mortality -0.104 0.169 Factor1 Factor2...
2001 Apr 21
0
Re: PR#886: Error (?) in documentation of 'swiss'
...'swiss' datafram in the R base package. The description accurately matches what is said in the Mosteller and Tukey source quoted, but according to the data archived at Princeton (links from http://opr.princeton.edu/archive/eufert/switz.html), the variable that Mosteller and Tukey report as infant mortality is actually the proportion of 'draftees' with education beyond primary school. Infant mortality is on the archived file, but the values are quite a lot different. Of course, it's possible that Mosteller and Tukey were right and the people who did the archiving at Princenton, l...
2007 May 09
1
step() in sink() and Sweave()
...ands within the step() body are: if (trace) message("Start: AIC=", format(round(bAIC, 2)), "\n", cut.string(deparse(as.vector(formula(fit)))), "\n") (with example() output:) Start: AIC=190.69 Fertility ~ Agriculture + Examination + Education + Catholic + Infant.Mortality And later: if (trace) print(aod[o, ]) (with example() output:) Df Sum of Sq RSS AIC - Examination 1 53.0 2158.1 189.9 <none> 2105.0 190.7 - Agriculture 1 307.7 2412.8 195.1 - Infant.Mortality 1 408.8...
2001 Apr 21
1
Re: PR#886: Error (?) in documentation of 'swiss'
...afram in the R base package. The description accurately > matches what is said in the Mosteller and Tukey source quoted, but > according to the data archived at Princeton (links from > http://opr.princeton.edu/archive/eufert/switz.html), the variable that > Mosteller and Tukey report as infant mortality is actually the proportion > of 'draftees' with education beyond primary school. Infant mortality is on > the archived file, but the values are quite a lot different. Of course, > it's possible that Mosteller and Tukey were right and the people who did > the archiv...
1997 Dec 02
1
R-alpha: two-sided to one-sided formula
At times we want to convert a two-sided formula to a one-sided formula. In S we can do this by dropping the second entry in the formula. In R that object no longer has a formula class. R> ttt <- score ~ age | Infant R> class(ttt) [1] "formula" R> length(ttt) [1] 3 R> ttt[-2] [[1]] ~ [[2]] age | Infant R> class(ttt[-2]) NULL R> do.call("~", ttt[-(1:2)]) ~age | Infant In general it would not be a good idea to propagate the formula class to subsets but it does ma...
2006 Jul 06
0
read.xport issues
...± CHYPER Hypertension, Chronic PHYPER Hypertension, Pregnancy-Associated Á CLAMP Eclampsia INCERVIXIncompetent Cervix PRE4000 Previsou Infant 4000+ grams PRETERM Previou Preterm RENAL Renal Disease é RH RH Sensitization !UTERINE Uterine Bleeding...
2004 Dec 07
1
how to test the existence of a name in a dataframe
...re exists already a name (which is incidentally a substring of another name) in a dataframe. I did e.g.: > data(swiss) > names(swiss) [1] "Fertility" "Agriculture" "Examination" "Education" [5] "Catholic" "Infant.Mortality" > ! is.null(swiss$EduX) [1] FALSE > ! is.null(swiss$Edu) [1] TRUE I did not expect to get TRUE here because ``Edu'' does not exist as name of ``swiss''. I did finally: > 'Edu' %in% names(swiss) for which I got the expected FALSE. My question: Wh...
2012 Jan 19
1
Setting ups.delay.shutdown in powerware 9135
...te the shutdown of machines. Before, I did use a propietary program to work with this ups, and the daemon did poweroff the ups without problems. But, now, I have only a openfiler based machine, and the propietary program don't run (but, I did find nut to replace it). Can any help me? TIA jorge infante rosario - santa fe - argentina -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.alioth.debian.org/pipermail/nut-upsuser/attachments/20120119/ebeba709/attachment.html>
2001 Mar 28
0
Error (?) in documentation of 'swiss' data in R base package (PR#886)
...'swiss' datafram in the R base package. The description accurately matches what is said in the Mosteller and Tukey source quoted, but according to the data archived at Princeton (links from http://opr.princeton.edu/archive/eufert/switz.html), the variable that Mosteller and Tukey report as infant mortality is actually the proportion of 'draftees' with education beyond primary school. Infant mortality is on the archived file, but the values are quite a lot different. Of course, it's possible that Mosteller and Tukey were right and the people who did the archiving at Princenton, l...
2002 Nov 13
4
[Newbie] Is there any support for work with grouped frequencies?
Hi, I have this table (BTW, published by FBI and representing age distribution of the WTC tragedy victims): "LABEL" "FREQ" "MIDPOINT" "1" "Infant (under 1)" 0 "2" "1 to 4" 5 "3" "5 to 8" 1 "4" "9 to 12" 3 "5" "13 to 16" 0 "6" "17 to 19" 3 "7" "20 to 24" 117 "8" "25 to 29" 341 &q...
2011 Jun 28
1
plotting survival curves with model parameters
Hello. I am trying to write an R function to plot the survival function (and associated hazard and density) for a Siler competing hazards model. This model is similar to the Gompertz-Makeham, with the addition of a juvenile component that includes two parameters---one that describes the initial infant mortality rate, and a negative exponential that describes typical mortality decline over the juvenile period. The entire hazard is expressed as h(x) = a1*exp(-b1*x)+a2+a3*exp(b3*x) I've had success in plotting the curves using the following function: ######################################...
2006 Jul 24
2
Correlations by group
I'm aware that S N Krishna asked the same question. However, I have failed to implement the posted solution for running rank order correlations on multiple subsets of data using the by() function. Here is my problem: Take a set of data from two subjects, who provided numerical infant mortality (IM) estimates for five countries: sub <- c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2) #grouping variable = 5 rows x 2 subjects est <- c(60, 20, 260, 160, 42, 2, 1, 3, 7, 12) #response variable = 5 estimates x 2 subjects im <- c(4, 5, 7, 8, 10, 4, 5, 7, 8, 10) #a...
2009 Mar 06
1
fitting a gompertz model through the origin using nls
Dear all! I tried to fit Gompertz growth models to describe cummulative germination rates using nls. I used the following code: germ.model<-nls(percent.germ~a*exp(-b*exp(-k*day)),data=tab,start=list(a=100,b=10,k=0.5)) My problem is that I want that the fitted model goes through the origin, since germination cannot start before the experiment was started, and y-max should be 100. Does anyone
2007 Apr 20
2
sorting data in R
hello, I'd like know how to sort a data frame in R for example how I should do to sort by Catholic with swiss data frame like below thanks Fertility Agriculture Examination Education Catholic Infant.Mortality Courtelary 80.2 17.0 15 12 9.96 22.2 Delemont 83.1 45.1 6 9 84.84 22.2 Franches-Mnt 92.5 39.7 5 5 93.40 20.2 Moutier 85.8 36.5...
2006 Nov 21
1
NEWBIE: Help explaining use of lm()?
...(such as the amount of a hormone administered) to a dependent variable (such as the height of a cornstalk). Its output was a model that could state, "for every 10% increase in the hormone, the height increased by X%." The zelazo data are the ages at walking (in months) of four groups of infants, two controls and two experimentals subjected to different exercise regimens. I don't understand why lm() can be used at all in this circumstance. My initial attempt was to use t.test(), which the answer key does also. I would have never thought to use lm() except for the requirement in the pr...