search for: ineqlb

...um(mat%*%x) sum_pterm=sum(mat[1:N,]%*%x/all2) sum_x=sum(x) return(c(sum_pterm,sum_x)) } # the right hand side for the constraint eqB=c(1,budget) # the inequality function inequal1=function(x){ all3=sum(mat%*%x) p_b=mat[1:BR,]%*%x/all3 return(as.vector(p_b)) } #the lower limit for inequalities ineqLB=rep(0.00001,BR) #the upper limit for the inequalities ineqUB=rep(1.00001,BR) # the lower and upper bounds for the variables LB=rep(0,CELL) UB=rep(1,CELL) #the seed for variables cells0=rep(.3,9) #solving the problem sol=solnp(cells0,fun=obj,eqfun=equal1,eqB=eqB,ineqfun =inequal1,ineqLB=ineqL...