search for: index_day

Displaying 1 result from an estimated 1 matches for "index_day".

2012 Mar 29
1
Error: argument of length 0
...ot;year","day",ecosection$OBJECTID))} for (i in 1:numberFires){ index_yr<-which(FM100$year==years[i]) # file default 366 days/year w/ Feb 29 set to NAN, but DOY accounts for leap years when # assigning Day-of-year for mm-dd-yyyy if (years[i]%%4 != 0) {index_day<-explanatory.variables$DOY[i]+1} if (years[i]%%4 == 0) {index_day<-explanatory.variables$DOY[i]} index<-index_yr[index_day] # 10 day antecedent FM100 average explanatory.variables$FM100[i]<-mean(FM100[(index-9):index,columnID]) } rm(FM100) prin...