Displaying 2 results from an estimated 2 matches for "inddf".
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indf
2002 Nov 26
2
URGENT Help required
...s in the same matrix (models) one after the
other.
# Set general variables & matrix
myDataFrame <- read.table("path",header=T)
models <- matrix(nrow = 20, ncol =8)
X <- matrix(nrow = 1, ncol = 6)
compt <- 1
deb <- 0
fin <- 0
# Runsanalysis
myFunction <- function(IndDF)
{
indDF <- as.data.frame(IndDF)
for (i in 2:(length(IndDF)-1))
{
for (j in ((i+1):(length(IndDF))))
{
for (k in 0:5)
{
deb <- dim(IndDF)[1]-k*21-100
fin <- dim(IndDF)[1]-k*21...
2002 Nov 26
0
scope (was URGENT Help required)
...print(x); x <- 5; print(x) }
> f()
[1] 10
[1] 5
> x
[1] 10
I suppose the "usual" way of doing what you wanted to do is make the objects
you want inside the function (rather than the workspace), and return a list
containing them. E.g., something like:
myFunction <- function(IndDF)
{
models <- matrix(nrow = 20, ncol =8)
X <- matrix(nrow = 1, ncol = 6)
compt <- 1
indDF <- as.data.frame(IndDF)
for (i in 2:(length(IndDF)-1))
{
[whatever you need to do...]
}
return(list(models = models, compt = compt))
}
Andy
-----Origin...