Displaying 4 results from an estimated 4 matches for "ifnul".
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ifsul
2009 Feb 15
3
conditions on association include, hacky but more or less solved
...:include => [:trait_values =>
[:key_factors]],
:joins => " AND
key_factors.entity_id="+@entity.id.to_s,
:conditions => "trait_values.trait_id =
traits.id
AND IFNULL
(key_factors.id,0) = IFNULL(key_factors.id,0)",
Which finally produces
FROM `traits`
LEFT OUTER JOIN `trait_values` ON trait_values.trait_id = traits.id
LEFT OUTER JOIN `key_factors` ON key_factors.trait_value_id =
trait_values.id
A...
2010 Jul 25
1
Left Outer Join 2 DF's on Multiple Conditions
Hi,
I am trying to execute the following SQL statement using two data frames:
tab1, tab2 : Two Tables
Select tab1.*, tab2.*, tab1.tobiiTime - tab2.ruiTime as timeDiff,
IFNULL(n-m, -9999999) as alwaysIncrement
FROM tab1
LEFT OUTER JOIN tab2 On tab1.data1 - tab2.mouseX = 0 And tab1.data2 -
tab2.mouseY = 0
I am trying to do the following in R:-
*#Getting error here:*
data <- merge(tab1,tab2, all.x=TRUE, by=(data$data1 - data$mouseX == 0),
by=(data$...
2009 Nov 09
3
How can I improve a Ruby on Rails code that hast a lot of SQL as strings?
...es, :as => :voteable
def self.ranking(user_id)
Item.find(:all,
# items.* for all the Item attributes, score being the sum of votes,
user_vote is the vote of user_id (0 if no vote) and voter_id is just user_id
for latter reference.
:select => "items.*,
IFNULL(sum(all_votes.value), 0) as score,
user_votes.value as user_vote,
\"#{user_id}\" as voter_id",
# The first join gets all the votes for a single item (to be summed
latter).
# The second join gets the vote for a single user for a single...
2008 Jul 26
4
Data length mismatch.
I have two vectos (list) that represent a years of data. Each "row" is represented by the day of year and the quantity that was sold for that day. I would like to form a new vector that is the difference between the two years of data. A sample of A (and similarly B) looks like:
> A[1:5,]
DayOfYear x
1 1 1429
2 2 3952
3 3 3049
4 4 2844
5 5