search for: idiv8

Hi, I noticed that when dividing with signed 8-bit values the IR uses a 32-bit signed divide, however, when unsigned 8-bit values are used the IR uses an 8-bit unsigned divide. Why not use a 8-bit signed divide when using 8-bit signed values? Here is the C code and IR: char idiv8(char a, char b) { char c = a / b; return c; } define signext i8 @idiv8(i8 signext %a, i8 signext %b) nounwind readnone { entry: %conv = sext i8 %a to i32 %conv1 = sext i8 %b to i32 %div = sdiv i32 %conv, %conv1 %conv2 = trunc i32 %div to i8 ret i8 %conv2 } unsigned char div8(unsigne...