Displaying 1 result from an estimated 1 matches for "i___".
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2009 Sep 03
1
Running an expression 1MN times using embedded R
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#define R_NO_REMAP
#include <Rversion.h>
#include <R.h>
#include <Rdefines.h>
#include <Rinternals.h>
#include <Rinterface.h>
#include <Rembedded.h>
#include <R_ext/Boolean.h>
#include <R_ext/Parse.h>
#include <R_ext/Rdynload.h>
const int i___ = 1;
#define is_bigendian() ( (*(char*)&i___) == 0 )
extern void (*ptr_R_ShowMessage)(const char *);
extern void (*ptr_R_WriteConsole)(const char *, int);
extern int (*ptr_R_ReadConsole)(char *, unsigned char *, int, int);
extern void (*ptr_R_WriteConsoleEx)(const char *, int , int );
SEXP rh...