Displaying 9 results from an estimated 9 matches for "hydrologie".
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hydrologic
2008 Jun 25
1
confidence bounds using contour plot
..., pch=19, cex=0.5)
contour(kerneld, levels = confidencebound, col="red", add = TRUE)
--
How can I calculate the right contour containing 95% of the values?
Thank's for your help.
Pascal
R 2.7.0, Win XP
--
Pascal H?nggi
Universit?t Bern
Geographisches Institut, Gruppe f?r Hydrologie
Hallerstrasse 12
CH-3012 Bern
+41 (0)31 631 54 71
pascal.haenggi at hydrologie.unibe.ch
http://www.hydrologie.unibe.ch
--
2007 Apr 19
1
read.table with more than one sep
Dear List,
somebody knows, if the following operation can be done in an easier way?
The data rows which should be read into R look like that:
4547;1970.01.01 00:00-1970.01.01 01:00; noData
Unitil now we are doing this procedure:
1. Dividing columns which are separated by ";"
=> temp <- read.table(file ,sep=';', na.strings='noData',
strip.white=TRUE)
=>
2010 Dec 08
2
piechart
...","M","A","M","J","J","A","S","O","N","D"),clockwise=T)
points (0,0,col="black",cex=20,pch=1
--
-------------------------------------------------
UDATA Umweltschutz und Datenanalyse
Hydrologie, Klimafolgenforschung, Boden- und Grundwasserschutz
Carl-Sch?ller-Str. 30 1/3, 95444 Bayreuth
www.udata.de
Tel. 0921/78638573 (Durchwahl)
wendel at udata.de
Firmensitz: Neustadt an der Weinstra?e
Inhaber: Dr. J?rg Scherzer
2008 Apr 17
1
Moving from Splus to R: irregular and regular time series
...h packages have been developped separately and I don't
see how I could specify time to be able to plot regular and irregurlar
time series on the same graph --- if it is possible in R--.
Thanks in advance for your answer
Best regards
Isabelle
--
Isabelle BRAUD
Cemagref
Unit? de recherche Hydrologie-Hydraulique
3bis quai Chauveau
CP 220
69336 Lyon C?dex 9
Tel: 04 72 20 87 78
Fax: 04 78 47 78 75
E-mail: isabelle.braud at cemagref.fr
2007 May 31
1
plotting variable sections of hourly time series data using plot.zoo
Dear list,
I have to look examine hourly time - series and would like to plot variable
section of them using plot.zoo.
Hourly time series data which looks like this:
YYYY MM DD HH P-uk P-kor P-SME EPOT EREA RO R1
R2 RGES S-SNO SI SSM SUZ SLZ
2003 1 1 1 0.385 0.456 0.021 0.000 0.000 0.000 0.013
0.223 0.235 0.01 0.38
2009 Nov 04
4
read.table (again)
...that every 4 digits, a new number begins?
I treif different things with "sep".
data <- read.table ("RA19930101.txt",header=F,sep=)
Thanks for your help again in this topic.
Sybille
--
-------------------------------------------------
UDATA Umweltschutz und Datenanalyse
Hydrologie, Klimafolgenforschung, Boden- und Grundwasserschutz
carl-Sch?llerstr. 30 1/3 95444 Bayreuth<<
www.udata.de
Tel. 0921/78638573 (Durchwahl)
wendel at udata.de
Firmensitz: Neustadt an der Weinstra?e
Inhaber: Dr. J?rg Scherzer
2004 Nov 16
0
From S-Plus to R
...rent frequencies and even irregular
time
series. Is it still possible in R?
Thanks in advance for your answers.
Best wishes
Isabelle Braud
***************************************************************
Isabelle BRAUD
Chargée de recherche au LTHE-Grenoble/CEMAGREF-Lyon
CEMAGREF
Unité de Recherche Hydrologie-Hydraulique
3 bis, Quai Chauveau, CP 220
69336 Lyon Cedex 9
Tel: 04 72 20 87 78 (from abroad 33 4 72 20 87 78)
Fax: 04 78 47 78 75 (from abroad 33 4 78 47 78 75)
E-mail: braud at lyon.cemagref.fr
ou Isabelle.Braud at hmg.inpg.fr
[[alternative HTML version deleted]]
2009 Apr 23
0
How to construct confidence bands from a gls fit?
...lines(as.numeric(time(LakeHuron)),predict(lm.hu,interval=c("conf"))[,3],lty=2,col=2)
## predict of the gls class does not contain confidence intervals
lines(as.numeric(time(LakeHuron)),predict(gls.hu,interval=c("conf")),lty=1,col=4)
Thank you,
Maik
--
Maik Renner
Institut f?r Hydrologie und Meteorologie
Technische Universit?t Dresden
2012 Mar 25
2
avoiding for loops
I have data that looks like this:
> df1
group id
1 red A
2 red B
3 red C
4 blue D
5 blue E
6 blue F
I want a list of the groups containing vectors with the ids. I am
avoiding subset(), as it is
only recommended for interactive use. Here's what I have so far:
df1 <- data.frame(group=c("red", "red", "red", "blue",