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Greetings, I am new to R and have been comparing CPH survival analysis hazard ratios between R and SAS PhReg. The binary covariates' HRs are the same, however the continuous variables, for example age, have quite different HRs although in the same direction. SAS PhReg produces HRs which are the change in risk for every one increment change in the independent variable. How do I interpret the HRs produced by R? Thanks much, C...

...), data=myDataFrame) # more restricted fit2 <- gls(y ~ dose, data=myDataFrame) anova.results <- anova(fit1, fit2) anova.results } df <- data.frame( y=c(12,3,45,1,53,6), dose=c(0,10,200,0,10,200), time=c("4.00 hrs", "4.00 hrs", "6.00 hrs", "6.00 hrs", "8.00 hrs", "8.00 hrs"), time.hours=c(4, 4, 6, 6, 8, 8), rep=rep("a", 6) ) ## This leads to the following error: ## Error in anova.lme(...

...we ran into the fsck issue while rebooting one of the Oracle RAC nodes running on Linux RHEL 5.2. It was hanging for 1.5 hours During the reboot, OS portion went fine, then it activated the data volumes in all data vg's with [OK] Then displayed message: Checking filesystems - and it took it 1.5 hrs, then it finished the reboot. Last weekend we rebooted the same box and faced the same issue, however, we sent the break, commented out (last "0" in /etc/fstab did not work neither) all OCFS2 lines in /etc/fstab and it booted fine. Then we mount -a them and life was good. Also we adde...

...tatus)~a[,i], data=a)) I used it to fit the Cox Proportional Hazard models separately for every available parameter (columns 3:12) in my data set - with intention to compare the Hazard Ratios. However, some of my variables are in range 0.1 to 1.6, others in range 5000 to 9000. How do I compare HRs between such variables? I have rescaled all the variables to be in 0 to 1 range - is this the proper way to go? Is there a way to somehow calculate the same HRs (as for rescaled parameters) from the HRs for original parameters? Many thanks in advance. -- Michal J. Figurski, PhD HUP, Pathology...

Peter, that finally worked. hrs = seq(1, 24, 1) g = bwplot(tt~OnHFact |Runway, data=gdf, ylab="Taxi time (min)", main=title, xlab="Hour of day", par.strip.text=list(cex=0.7), rot=90, xlim=c(0, 25), drop.unused.levels=FALSE, scales=list(x = list(rot=90, cex=.6...

I am trying to merge two data frames, but one of the column headings are different in the two frames. How can I rjoin or rbind the tho frames? Johnny # Generate 2 blocks by confounding on abc d1 <- conf.design(c(1,1,1), p=2, block.name="blk", treatment.names = c("A","B","C")) d2 <- conf.design(c(1,1,1), p=2, block.name="blk",

Hi, I am working with a dataset for sometime and I need some help in parsing some data. There is a column called "Duration" which has data like following: 2 minutes => 120 2 min => 120 10 seconds =>10 2 hrs =>7200 2-3 minutes => 150 or 120 5 minutes (when i arrived => 300 Flyby approx 20 sec. => 20 felt like 10 mins but tim => 600 I need to convert them to numerics as given. Any help in this regard will be highly appreciated. Thanks Susanta [[alternative HTML version deleted]]

...-----Original Message----- From: Icecast [mailto:icecast-bounces at xiph.org] On Behalf Of webmaster at berean-biblechurch.org Sent: Tuesday, 2 June 2020 1:35 p.m. To: Icecast streaming server user discussions Subject: Re: [Icecast] Icecast Stream Keeps Repeating Sent Friday 29th May 2020 At: 16.19.hrs. GMT I've had this same problem. That is why I have been asking about how to remove the no-cache header. But no answer in the ether... Justin On 2020-05-29 11:48, Jordan Erickson wrote: > Hi, > > > On 5/29/20 8:20 AM, Les Durno wrote: >> However, when I stop my audio s...

http://bugzilla.mindrot.org/show_bug.cgi?id=119 ------- Additional Comments From stevesk at pobox.com 2002-03-31 05:22 ------- what is the timeout issue? timeouts can be caused by filters that maintain connection state and have timeouts; or TCP keepalives or ??? this should probably be "invalid" ------- You are receiving this mail because: ------- You are the assignee for the

http://bugzilla.mindrot.org/show_bug.cgi?id=119 Summary: Occassionally, SSH failed to connect and timeout after 2 hrs! Product: Portable OpenSSH Version: older versions Platform: ix86 OS/Version: Linux Status: NEW Severity: normal Priority: P2 Component: ssh AssignedTo: openssh-unix-dev at mindrot.org ReportedBy: angus...

I've had this same problem. That is why I have been asking about how to remove the no-cache header. But no answer in the ether... Justin On 2020-05-29 11:48, Jordan Erickson wrote: > Hi, > > > On 5/29/20 8:20 AM, Les Durno wrote: >> However, when I stop my audio source, after some seconds, eg, ten, >> then >> once that audio stream has finished, after

Hello Jordan, Many thanks for your prompt reply with your advice. I created a web page with only an HTML5 audio player, ( The page being on my desktop ), with the listening URL stream source code. I started a test stream and a few seconds later the stream was playing on my audio player, on my page, although with the audio repetitions being heard after about six seconds.So I thought that this

Hi, On 5/29/20 8:20 AM, Les Durno wrote: > However, when I stop my audio source, after some seconds, eg, ten, then > once that audio stream has finished, after about six seconds the audio stream repeats playing, > then does so after the same time interval, again for many times. Each time the volume of these > repetitions, decreases. This sounds like a listener client issue. It makes

...se when doing burn-in on our systems to monitor the time they have been running and the latest temps - we test under full load using cpuburn-1.4. #! /bin/csh # temp display shell script # ISSLLC sab 3/04 echo "" echo "Starting" echo "" @ counter_s = 0 @ minutes = 0 @ hrs = 0 echo "Burn Time = $hrs hrs $minutes mins $counter_s secs" echo "" while (1) sensors | grep emp sleep 10 echo "" @ counter_s += 10 if($counter_s == 60) then @ counter_s = 0 @ minutes += 1 if($minutes == 60) then @ minutes = 0 @ hrs += 1 endif endif echo &quo...

...= $ARGV[0]; my $cidname = $ARGV[1]; $safe_cidname = uri_escape($cidname); my $browser = LWP::UserAgent->new; my $url = "http://www.acme.com/input.php?"; $url .= "name=" . $safe_cidname . "&"; $url .= "number=" . $cidnum . "&"; ($min, $hrs, $day, $month, $year) = (localtime) [1,2,3,4,5]; $currentdate = sprintf("%02d/%02d/%02d", $day, $month+1, $year % 100); $currenttime = sprintf("%02d:%02d", $hrs,$min); $url .= "date=" . $currentdate . "&"; $url .= "time=" . $currenttime; #print...

Hello Icecast, I have successfully done a test audio stream to the free, "Icecast," server. However, when I stop my audio source, after some seconds, eg, ten, then once that audio stream has finished, after about six seconds the audio stream repeats playing, then does so after the same time interval, again for many times. Each time the volume of these repetitions, decreases. Even

..... 1918 59.1785 -14.5851 0.3895 44.9850 -0.0021 0.141E-06 1919 59.1816 -14.5622 0.3933 44.9972 0.0155 0.139E-06 1920 59.1637 -14.5666 0.4420 45.0219 0.0172 0.138E-06 Column 1, is index of hours on 3 hourly interval and starts from 1 Jan 2009, 00 hrs and run till 240 days of 2009. I want to convert Column 1 of above data in the format, 'year' , 'month', 'day', 'hour' Kindly help. Thanks, Regards, Yogesh My question is below Dear R Users, > > I have model simulated data for 240 days. > > The day...

Dear R-Help, With the attached data set, I am still getting incorrect bwplots > xyplot(gdf$tt~gdf$OnHour |gdf$Runway, data=gdf) # Is correct > bwplot(gdf$tt~gdf$OnHour |gdf$Runway, data=gdf, horizontal=FALSE) # Puts the boxes on the wrong x-axis values # look especially at 0 and 3. How do I fix this? What is happening? Thanks, Jim Rome

I posted a similar question, but feel it needs a bit more elaboration. I have a data frame (read from a csv file) that may have missing rows. Each day has 7 time intervals associated with it, with a range from 17:00 hrs to 18:00 hrs in 10 minute bins. What I am looking for is a script that will run through the data frame and insert "NA"in the Volume column for any dates that are missing a time interval. For example: Date Time Camera Volume 57 2009-10-09 5:00:00 PM MA...

...from survival package: > aml3<-survSplit(aml2,cut=c(5,10,20),end="time",start="start", event="status",episode="i") If I want to esimate hazard ratio for each of the time intervals 0-5, 5-10, 10-20 and >=20, would the following calculate such HRs? > coxph(Surv(start,time,status)~x*as.factor(i),data=aml3) Call: coxph(formula = Surv(start, time, status) ~ x * as.factor(i), data = aml3) coef exp(coef) se(coef) z p xNonmaintained 19.2 2.10e+08 10461 0.00183 1 as.factor(i)1...