Displaying 1 result from an estimated 1 matches for "hladane".
Did you mean:
haldane
2009 Feb 27
3
rounding problem
hi i am creating some variables from same data, but somewhere is different
rouding.
look:
P = abs(fft(d.zlato)/480)^2
hladane= sort(P,decreasing=T)[1:10]/480
pozicia=c(0,0,0,0,0)
for (j in 1:5){ for (i in 2:239){
if (P[i]/480==hladane[2*j-1]){pozicia[j]=i-1}}}
period=479/pozicia
> P[2]/334
[1] 0.0001279107
> hladane[1]
[1] 0.0001279107
> P[2]/334==hladane[1]
[1] FALSE
> abs(P[2]/334 - hlada...