Displaying 1 result from an estimated 1 matches for "hhhhhhhaaaaa".
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hhhhhhhhaaaa
2003 Sep 21
1
3 basic questions
...lt;-c(0,1,1,0,0,1,0,0,1)
> dim(x)<-c(3,3)
> types<-numeric(3)
> for (i in 1:3) {
+ j<-1
+ while (x[i,j]!=1) j<-j+1
+ if (j==4) types[i]<-0
+ else types[i]<-1
+ }
Error: subscript out of bounds
Any ideas about what is wrong?
Second)
I have a data file like this:
*data1 HHHHHHHHAAAAAABBBBBB...
*data2 HHHHHHHAAAAAABBBBBBB...
When I use read.table, all the characters are read as one variable.
How can I put each of them into a different column? Besides, I want to
discard the labels *data1 and *data2.
Third)
If the same file is like this:
*data1 HHHHHHHHAAAA
AABBBBB...
*da...