search for: hexmod

Hi, I'm wondering if someone has solved the problem of converting very large integers to hex. I know about format.hexmode and as.hexmode, but these rely on integers. The numbers I'm working with are overflowing and losing precision. Here's an example: x <- "6595137340052185552" # stored as character as.integer(x) # warning about inaccurate conversion format.hexmode(as.numeric(x)) # warnings abou...

..., which indirectly causes the environment of base::q, .GlobalEnv, to be loaded as a namespace, causing the error. Giving his replacement q function the environment getNamespace("base") avoids the problem. I can reproduce the problem by making a package that just calls setGeneric("as.hexmode",...) and a NAMEPACE file with exportMethods("as.hexmode"). If my .Rprofile puts a version of as.hexmode with environment .GlobalEnv into the base namespace, then I get the same error when trying to load the package. I suppose this is mostly a curiosity and unlikely to happen to m...

...to be loaded as a namespace, causing the error. >> Giving his replacement q function the environment getNamespace("base") >> avoids the problem. >> >> I can reproduce the problem by making a package that just calls >> setGeneric("as.hexmode",...) and a NAMEPACE file with >> exportMethods("as.hexmode"). If my .Rprofile puts a version of as.hexmode >> with environment .GlobalEnv into the base namespace, then I get the same >> error when trying to load the package. >> >>...

...environment > of base::q, .GlobalEnv, to be loaded as a namespace, causing the error. > Giving his replacement q function the environment getNamespace("base") > avoids the problem. > > I can reproduce the problem by making a package that just calls > setGeneric("as.hexmode",...) and a NAMEPACE file with > exportMethods("as.hexmode"). If my .Rprofile puts a version of as.hexmode > with environment .GlobalEnv into the base namespace, then I get the same > error when trying to load the package. > > I suppose this is mostly a curiosity and...

...ing the > error. > >> Giving his replacement q function the environment > getNamespace("base") > >> avoids the problem. > >> > >> I can reproduce the problem by making a package that just calls > >> setGeneric("as.hexmode",...) and a NAMEPACE file with > >> exportMethods("as.hexmode"). If my .Rprofile puts a version of > as.hexmode > >> with environment .GlobalEnv into the base namespace, then I get the > same > >> error when trying to load the package. &...

... and if you need to convert back: ?as.hexmode -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Apr 16, 2016 at 8:20 AM, Bert Gunter <bgunter.4567 at gmail.com> wrot...

Hello, we need to convert a logical vector to a (decimal) integer. Example: a=c(TRUE, FALSE, TRUE) (binary number 101) the function we are looking for should return dec2bin(a)=5 Is there a package for such a function or is it even implemented in the base package? We found the hexmode and octmode command, but not a binmode. We know how to program it ourselves however we are looking for a computationally efficient algorithm. Martin and Stefan

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...ppreciate some assistance if anyone can take a look at this code and offer advice. The RFC website does offer C code to execute the HMAC algorithm but I am not a C expert. ################ HMAC Code ############# library(digest) ########## hex to binary hexdat <- replicate(10, paste(format.hexmode(sample(16,4)-1),collapse='')) bin <- apply(outer(0:15,3:0,function(x,y) x%/%(2^y)%%2),1,paste,collapse="") names(bin) <- format.hexmode( 0:15 ) ## test ## cbind( hexdat, sapply( strsplit(hexdat,'') , function(x) paste( bin[x], collapse='' ) ) ) ##########...

...FFFFFFFDDDDDDDDDDCCCCC>>>>>>>>>" >> >> Each character in the above string represent a hexadecimal value. >> I want to translate those string into an array (of size == string length) >> which contain hexadecimal conversion. >> >> as.hexmode doesn't seem to do the job. > > Trying again, simplified > > ascii_str <- "ORQ>IK" > ascii_str2 <- "FDC" > > What do you want as output in both cases? I can partially understand the second > case, but not the first. > > Dieter > &g...

Dear All, I am sure this is a one-liner, but I cannot find the R command to generate the LaTex symbols \perp and \parallel. Consider for instance the figure (one can use any kind of data for the plot) pdf("friction_linear_chain_perpendicular.pdf") par( mar = c(4.5,5, 2, 1) + 0.1) plot(data[ ,1], data[

...o Three h 0.08104575 0.3891798 0.1666667 s 1.00000000 1.0000000 1.0000000 v 1.00000000 0.7490196 1.0000000 Bill Dunlap TIBCO Software wdunlap tibco.com On Sat, Apr 16, 2016 at 8:27 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > ... and if you need to convert back: ?as.hexmode > > > -- Bert > > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along > and sticking things into it." > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > On Sat, Apr 16, 2016 at 8...

Hi, do you know, a method to convert an decimal value (integer) to the corresponding hexadecimal value ? thinks for help. Romain -- Lorrilli?re Romain UMR 8079 Laboratoire Ecologie, Syst?matique et Evolution B?t. 362 Universit? Paris-Sud 91405 Orsay cedex France tel : 01 69 15 56 85 fax : 01 69 15 56 96 mobile : 06 81 70 90 70 email : romain.lorrilliere at ese.u-psud.fr

If I type a character using \U syntax that has more than 4 digits, I get the wrong character. For example, "\U1d4d0" should print a mathematical bold script capital A. See http://www.fileformat.info/info/unicode/char/1d4d0/index.htm On my machine, it prints the Hangul character corresponding to "\Ud4d0" http://www.fileformat.info/info/unicode/char/d4d0/index.htm It seems

...# 8-bit to \u0000 ascii <- paste0("\\u", chartr(" ","0",formatC(as.character(raw),width=4))) else if(length(raw)==2 && bytes==1) # 16-bit to \x00, if possible if(utf8ToInt(char) <= 255) ascii <- paste0("\\x", format.hexmode(utf8ToInt(char))) else { ascii <- fallback; warning(char, " could not be converted to 1 byte")} else if(length(raw)==2 && bytes==2) # UTF-8 to \u0000 ascii <- paste0("\\u", format.hexmode(utf8ToInt(char),width=4)) else { ascii &l...

...] TRUE > f <- try(as.factor( x ), silent = TRUE) > if(!inherits(f, 'try-error')) report(identical(f, as.factor( f ))) [1] TRUE > f <- try(as.function( x ), silent = TRUE) > if(!inherits(f, 'try-error')) report(identical(f, as.function( f ))) > f <- try(as.hexmode( x ), silent = TRUE) > if(!inherits(f, 'try-error')) report(identical(f, as.hexmode( f ))) [1] TRUE > f <- try(as.integer( x ), silent = TRUE) > if(!inherits(f, 'try-error')) report(identical(f, as.integer( f ))) [1] TRUE > f <- try(as.list( x ), silent = TRUE...

Dear List, I have a 47 species * 83 samples matrix containing percentage abundance data. I have two cluster analyses one of the samples and one of the species, and have ordered the rows and columns of the species by samples matrix according to these two cluster analyses. So far so good! Now what I want to do is create a plot with the species dendrogram at the top of the plot, the samples

...Y does as.Y() have no corresponding is.Y()? [1] "Date" "POSIXct" "POSIXlt" "dendrogram" [5] "difftime" "dist" "formula" "graphicsAnnot" [9] "hclust" "hexmode" "octmode" "person" [13] "personList" "roman" 3. For which Z does is.Z() just call inherits(., "Z")? [1] "data.frame" "factor" "numeric_version" "ordered" [5] "package...

I have a simple bar chart with annual precipitation (jan to dez). I want to plot, above each bar (on a line), a square wich is color based on a scale (0-100%). With 0 being white and 100 black, like a gradient. Is it possible? How to? Thanks -- Fernando Andreacci [[alternative HTML version deleted]]

?strtoi You'll have to remove the "#" first, e.g. via substring() -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Sat, Apr 16, 2016 at 5:47 AM, Atte Tenkanen <attenka at utu.fi> wrote: > Hi, > > How