Displaying 6 results from an estimated 6 matches for "herbivory".
2008 Jan 28
2
matrix creation
...0.09,0.166666667,0.31,0.42,NA,0.00, 0.00,0,0.00,0.00,NA,0.00,
0.00,0,0.00,0.00,NA,0.00,
0.26,0.166666667,0.19,0.00,NA,0.00, 0.58,0.666666667,0.47,0.58,0,0.00),
nrow = 6, ncol = 6,
dimnames = list(c("Vegetative", "Vegetative with herbivory",
"Reproductive",
"Reproductive with herbivory", "Dormant", "Dead"),
c("Vegetative", "Vegetative with herbivory", "Reproductive",
"Reproductive with herbivory", &...
2006 Apr 23
1
Comparing GLMMs and GLMs with quasi-binomial errors?
Dear All,
I am analysing a dataset on levels of herbivory in seedlings in an
experimental setup in a rainforest.
I have seven classes/categories of seedling damage/herbivory that I want to
analyse, modelling each separately.
There are twenty maternal trees, with eight groups of seedlings around each.
Each tree has a TreeID, which I use as the random e...
2009 May 01
1
computationally singular and lack of variance parameters in SEM
...ault(C) :
system is computationally singular: reciprocal condition number =
2.2449e-20
In addition: Warning message:
In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names =
vars, :
The following variables have no variance or error-variance parameter
(double-headed arrow):
Ants, Herbivory
The model is almost surely misspecified; check also for missing covariances.
I have tried my data set with both a correlation (cor) and a variance (var)
matrix, but both produce the same error, and I'm not sure which one is
correct. The error message about the variables that have no variance...
2009 May 27
1
Hierarchical glm with binomial family
...to do a hierarchical glm with binomial family but am unsure
about how to write the syntax which involves nesting.
I want to test whether the risk of being attacked by Herbivores for
Meadowsweet plants is significantly dependent on the Distance to
heterospecific source plants.
Dependent variable = Herbivory (yes/no)
Explanatory continuous variable = Distance to heterospecific source plant
Distance should be nested within Subpopulation which in turn should be
nested within Population.
The number of replicates per subpopulation varies between 8 and 36.
The number of subpopulations per population varies...
2007 Nov 15
3
Ancova doesn't return test statistics
Dear all,
I'm quite sure that this is a stupid question, but I'll ask anyway.
I want to perform an ANCOVA with two continuous factors and three
categorical factors.
Plant population growth rate (GR) = dependent variable
Seed reduction due to herbivory (SR) = continuous explanatory variable
Herbivore species (HS, 2 levels) = categorical explanatory variable
Population (Pop, 24 levels) = categorical explanatory variable
Population size (Popsize) = continuous explanatory variable
Year (Year, 16 levels) = categorical explanatory variable
My model i...
2009 Jun 01
1
installing sn package
...to do a hierarchical glm with binomial family but am unsure
about how to write the syntax which involves nesting.
I want to test whether the risk of being attacked by Herbivores for
Meadowsweet plants is significantly dependent on the Distance to
heterospecific source plants.
Dependent variable = Herbivory (yes/no)
Explanatory continuous variable = Distance to heterospecific source plant
Distance should be nested within Subpopulation which in turn should be
nested within Population.
The number of replicates per subpopulation varies between 8 and 36.
The number of subpopulations per population varies...