search for: herbivory

Displaying 6 results from an estimated 6 matches for "herbivory".

2008 Jan 28
2
matrix creation
...0.09,0.166666667,0.31,0.42,NA,0.00, 0.00,0,0.00,0.00,NA,0.00, 0.00,0,0.00,0.00,NA,0.00, 0.26,0.166666667,0.19,0.00,NA,0.00, 0.58,0.666666667,0.47,0.58,0,0.00), nrow = 6, ncol = 6, dimnames = list(c("Vegetative", "Vegetative with herbivory", "Reproductive", "Reproductive with herbivory", "Dormant", "Dead"), c("Vegetative", "Vegetative with herbivory", "Reproductive", "Reproductive with herbivory", &...
2006 Apr 23
1
Comparing GLMMs and GLMs with quasi-binomial errors?
Dear All, I am analysing a dataset on levels of herbivory in seedlings in an experimental setup in a rainforest. I have seven classes/categories of seedling damage/herbivory that I want to analyse, modelling each separately. There are twenty maternal trees, with eight groups of seedlings around each. Each tree has a TreeID, which I use as the random e...
2009 May 01
1
computationally singular and lack of variance parameters in SEM
...ault(C) : system is computationally singular: reciprocal condition number = 2.2449e-20 In addition: Warning message: In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names = vars, : The following variables have no variance or error-variance parameter (double-headed arrow): Ants, Herbivory The model is almost surely misspecified; check also for missing covariances. I have tried my data set with both a correlation (cor) and a variance (var) matrix, but both produce the same error, and I'm not sure which one is correct. The error message about the variables that have no variance...
2009 May 27
1
Hierarchical glm with binomial family
...to do a hierarchical glm with binomial family but am unsure about how to write the syntax which involves nesting. I want to test whether the risk of being attacked by Herbivores for Meadowsweet plants is significantly dependent on the Distance to heterospecific source plants. Dependent variable = Herbivory (yes/no) Explanatory continuous variable = Distance to heterospecific source plant Distance should be nested within Subpopulation which in turn should be nested within Population. The number of replicates per subpopulation varies between 8 and 36. The number of subpopulations per population varies...
2007 Nov 15
3
Ancova doesn't return test statistics
Dear all, I'm quite sure that this is a stupid question, but I'll ask anyway. I want to perform an ANCOVA with two continuous factors and three categorical factors. Plant population growth rate (GR) = dependent variable Seed reduction due to herbivory (SR) = continuous explanatory variable Herbivore species (HS, 2 levels) = categorical explanatory variable Population (Pop, 24 levels) = categorical explanatory variable Population size (Popsize) = continuous explanatory variable Year (Year, 16 levels) = categorical explanatory variable My model i...
2009 Jun 01
1
installing sn package
...to do a hierarchical glm with binomial family but am unsure about how to write the syntax which involves nesting. I want to test whether the risk of being attacked by Herbivores for Meadowsweet plants is significantly dependent on the Distance to heterospecific source plants. Dependent variable = Herbivory (yes/no) Explanatory continuous variable = Distance to heterospecific source plant Distance should be nested within Subpopulation which in turn should be nested within Population. The number of replicates per subpopulation varies between 8 and 36. The number of subpopulations per population varies...