Displaying 4 results from an estimated 4 matches for "height1".
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2010 Mar 25
1
Problem with reshaping data from wide to long format
...(nonsense) data:
> dput(perus2)
structure(list(id = c(30L, 38L, 21L, 12L, 22L, 28L, 31L, 44L,
8L, 47L, 23L, 20L, 41L, 42L, 29L, 50L, 5L, 33L, 4L, 17L, 11L,
1L, 18L, 6L, 9L, 32L, 16L, 14L, 39L, 48L, 37L, 43L, 25L, 27L,
35L, 40L, 45L, 49L, 2L, 34L, 10L, 15L, 24L, 26L, 46L, 7L, 13L,
3L, 19L, 36L), height1 = c(157.10664436, 162.77883643, 162.57095167,
155.82784611, 158.17430233, 156.21247668, 159.33063095, 160.47626229,
157.54657592, 155.01414518, 158.5172723, 162.89026674, 156.08622305,
159.32250375, 162.23610226, 160.21190346, NA, 155.54527115, 155.94912976,
160.49239576, 159.29210577, 158.93378272...
2004 Oct 14
2
fidelity of generated raster images (R and perl)
...t($out "bitmap('/usr/local/mycrow/tmp/out.png', type = 'png256',
height = ".(int($height*68/64)/64).", width =
".(int($width*69/64)/64).", res = 64, pointsize=0)\n");
print($out 'par(mar=c(0,0,0,0))'."\n");
my $width1 = $width-1;
my $height1 = $height-1;
print($out <<END);
plot.new()
plot.window(c(0,$width1),c(0,$height1))
rect(m[,1], m[,2], m[,1], m[,2], col="black", border="black")
There are alternatives to rect (plot with type="p", pch=".", etc)
and I have also tried png() instead of bi...
2007 Mar 07
1
2 commits - libswfdec/swfdec_script.c test/trace
...dd GotoFrame2 test
diff --git a/test/trace/Makefile.am b/test/trace/Makefile.am
index 2368dc6..a0fa2ca 100644
--- a/test/trace/Makefile.am
+++ b/test/trace/Makefile.am
@@ -69,6 +69,8 @@ EXTRA_DIST = \
goto4.swf.trace \
goto5.swf \
goto5.swf.trace \
+ gotoframe.swf \
+ gotoframe.swf.trace \
height1.swf \
height1.swf.trace \
height2.swf \
diff --git a/test/trace/gotoframe.swf b/test/trace/gotoframe.swf
new file mode 100755
index 0000000..0aa1970
Binary files /dev/null and b/test/trace/gotoframe.swf differ
diff --git a/test/trace/gotoframe.swf.trace b/test/trace/gotoframe.swf.trace
new file...
2012 Nov 29
1
Error 0ps.factor: level sets of factors are different
I have two data sets: "new" and "combo". Within both data set, each row
pertains to a unique individual. The "combo" data set is a subset of the
"new" data set, meaning that all individuals within "combo" are within "new"
but not all individuals within "new" are within "combo". Thus, nrow(new) >
nrow(combo).
Each